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Define the following: i- The function ii- Function range. If f(x) = x²−3, g(x) = 3x +1 Find: i- (f)(2) ii- g(2) iii- (2)

Mathematics

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Answer

f(2)=1f(2) = 1

g(2)=7g(2) = 7

fg(2)=17\frac{f}{g}(2) = \frac{1}{7}

Step-by-step solution

6 steps

Question One:

A-(1) Define the following:

  • i- The function A function is a relation between a set of inputs (called the domain) and a set of permissible outputs (called the codomain) with the property that each input is related to exactly one output.

  • ii- Function range The range of a function is the set of all actual output values that the function produces for the given inputs in its domain.

A-(2) If f(x)=x2−3f(x) = x^2 - 3, g(x)=3x+1g(x) = 3x + 1 Find:

  • i- (f)(2)(f)(2)
  1. Substitute x=2x=2 into the function f(x)f(x).

    $$
    f(2) = (2)^2 - 3
    $$
    
  2. Calculate the value.

    $$
    f(2) = 4 - 3
    $$
    $$
    f(2) = \boxed{1}
    $$
    
    • ii- g(2)g(2)
  3. Substitute x=2x=2 into the function g(x)g(x).

    $$
    g(2) = 3(2) + 1
    $$
    
  4. Calculate the value.

    $$
    g(2) = 6 + 1
    $$
    $$
    g(2) = \boxed{7}
    $$
    
    • iii- fg(2)\frac{f}{g}(2)
  5. This expression means f(2)g(2)\frac{f(2)}{g(2)}.

    Use the values calculated in parts i and ii. fg(2)=f(2)g(2) \frac{f}{g}(2) = \frac{f(2)}{g(2)}

  6. Substitute the values of f(2)f(2) and g(2)g(2).

    $$
    \frac{f}{g}(2) = \frac{1}{7}
    $$
    $$
    \frac{f}{g}(2) = \boxed{\frac{1}{7}}
    $$
    
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