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Solve the following problems: 1. 7 − 2x > 15 − 4x. 2. p2(q-1) when p=2 and q=3/4. 3. Antwi has 20 mangoes and 20% are rotten. How many are not rotten? 4. Which is not a composite number?

Mathematics

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Answer

A

x>4x > 4

Step-by-step solution

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Here are the solutions to the multiple-choice questions:

1. Solve 7−2x>15−4x7 - 2x > 15 - 4x.

  1. Add $4x$ to both sides of the inequality.

    7−2x+4x>15−4x+4x7 - 2x + 4x > 15 - 4x + 4x 7+2x>157 + 2x > 15
  2. Subtract 7 from both sides.

    7+2x−7>15−77 + 2x - 7 > 15 - 7 2x>82x > 8
  3. Divide both sides by 2.

    2x2>82\frac{2x}{2} > \frac{8}{2} x>4x > 4

    The correct option is A. x>4x > 4.

    2. Evaluate p2(q−1)p^2(q-1) when p=2p=2 and q=34q=\frac{3}{4}.

  4. Substitute the given values of pp and qq into the expression.

    p2(q−1)=(2)2(34−1)p^2(q-1) = (2)^2\left(\frac{3}{4}-1\right)
  5. Calculate the value inside the parenthesis.

    34−1=34−44=−14\frac{3}{4}-1 = \frac{3}{4}-\frac{4}{4} = -\frac{1}{4}
  6. Calculate p2p^2.

    (2)2=4(2)^2 = 4
  7. Multiply the results.

    4×(−14)=−14 \times \left(-\frac{1}{4}\right) = -1

    The correct option is B. -1.

    3. Antwi has 20 mangoes and 20% are rotten. How many of them are not rotten?

  8. Calculate the number of rotten mangoes.

    Rotten mangoes=20% of 20=20100×20=15×20=4\text{Rotten mangoes} = 20\% \text{ of } 20 = \frac{20}{100} \times 20 = \frac{1}{5} \times 20 = 4
  9. Calculate the number of mangoes that are not rotten.

    Not rotten mangoes=Total mangoes−Rotten mangoes\text{Not rotten mangoes} = \text{Total mangoes} - \text{Rotten mangoes} Not rotten mangoes=20−4=16\text{Not rotten mangoes} = 20 - 4 = 16

    The correct option is A. 16.

    4. Which of the following is not a composite number?
    A composite number is a positive integer that has at least one divisor other than 1 and itself. A number that is not composite (and greater than 1) is a prime number.

    • A. 65: Divisible by 5 and 13 (e.g., 5×13=655 \times 13 = 65). So, 65 is composite.
    • B. 39: Divisible by 3 and 13 (e.g., 3×13=393 \times 13 = 39). So, 39 is composite.
    • C. 41: Only divisible by 1 and 41. So, 41 is a prime number.
    • D. 24: Divisible by 2, 3, 4, 6, 8, 12 (e.g., 2×12=242 \times 12 = 24). So, 24 is composite. The number that is not a composite number is 41. The correct option is C. 41.

    5. Mary receives a commission of 15% on articles sold in a week. If her commission was GH¢ 60.00, how much sales did she make?

  10. Let SS be the total sales.

    The commission is 15% of the total sales.

    15% of S=GH¢ 60.0015\% \text{ of } S = \text{GH¢ } 60.00
  11. Convert the percentage to a decimal or fraction.

    0.15×S=600.15 \times S = 60
  12. Solve for SS by dividing both sides by 0.15.

    S=600.15S = \frac{60}{0.15} S=6015100=60×10015S = \frac{60}{\frac{15}{100}} = 60 \times \frac{100}{15} S=4×100S = 4 \times 100 S=GH¢ 400.00S = \text{GH¢ } 400.00

    The correct option is B. GH¢ 400.00.

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