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Solve the following trigonometric equations graphically for 0^ leq x leq 360^ : a) x = 0.71 b) x = 0.31

Mathematics

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Answers

4 parts
a

x=45.2∘,134.8∘x = 45.2^\circ, 134.8^\circ

b

x=18.1∘,161.9∘x = 18.1^\circ, 161.9^\circ

c

x=36.9∘,143.1∘x = 36.9^\circ, 143.1^\circ

d

x=234.1∘,305.9∘x = 234.1^\circ, 305.9^\circ

Step-by-step solution

2 steps

To solve this problem, first, you need to draw the graph of y=sin⁡xy = \sin x for 0∘≤x≤360∘0^\circ \le x \le 360^\circ.

  1. Draw the graph of y=sin⁡xy = \sin x.

    • Draw a coordinate plane with the x-axis from 0∘0^\circ to 360∘360^\circ and the y-axis from −1-1 to 1.
    • Plot the key points for the sine function:
      • (0∘,0)(0^\circ, 0)
      • (90∘,1)(90^\circ, 1) (maximum value)
      • (180∘,0)(180^\circ, 0)
      • (270∘,−1)(270^\circ, -1) (minimum value)
      • (360∘,0)(360^\circ, 0)
    • Connect these points with a smooth curve to form the sine wave.
  2. Use the graph to solve the equations.

    To solve sin⁡x=k\sin x = k using the graph, draw a horizontal line at y=ky = k. The x-coordinates of the intersection points of this line with the sine curve are the solutions for xx.

    a) sin⁡x=0.71\sin x = 0.71
    Draw a horizontal line at y=0.71y = 0.71. Find the x-values where this line intersects the graph of y=sin⁡xy = \sin x.
    The principal value is x=arcsin⁡(0.71)≈45.2∘x = \arcsin(0.71) \approx 45.2^\circ.
    The second solution in the range 0∘≤x≤360∘0^\circ \le x \le 360^\circ is x=180∘−45.2∘=134.8∘x = 180^\circ - 45.2^\circ = 134.8^\circ.
    The solutions are approximately x=45.2∘,134.8∘\boxed{x = 45.2^\circ, 134.8^\circ}.

    b) sin⁡x=0.31\sin x = 0.31
    Draw a horizontal line at y=0.31y = 0.31. Find the x-values where this line intersects the graph of y=sin⁡xy = \sin x.
    The principal value is x=arcsin⁡(0.31)≈18.1∘x = \arcsin(0.31) \approx 18.1^\circ.
    The second solution is x=180∘−18.1∘=161.9∘x = 180^\circ - 18.1^\circ = 161.9^\circ.
    The solutions are approximately x=18.1∘,161.9∘\boxed{x = 18.1^\circ, 161.9^\circ}.

    c) sin⁡x=0.6\sin x = 0.6
    Draw a horizontal line at y=0.6y = 0.6. Find the x-values where this line intersects the graph of y=sin⁡xy = \sin x.
    The principal value is x=arcsin⁡(0.6)≈36.9∘x = \arcsin(0.6) \approx 36.9^\circ.
    The second solution is x=180∘−36.9∘=143.1∘x = 180^\circ - 36.9^\circ = 143.1^\circ.
    The solutions are approximately x=36.9∘,143.1∘\boxed{x = 36.9^\circ, 143.1^\circ}.

    d) sin⁡x=−0.81\sin x = -0.81
    Draw a horizontal line at y=−0.81y = -0.81. Find the x-values where this line intersects the graph of y=sin⁡xy = \sin x.
    First, find the reference angle: α=arcsin⁡(0.81)≈54.1∘\alpha = \arcsin(0.81) \approx 54.1^\circ.
    Since sin⁡x\sin x is negative, the solutions are in the third and fourth quadrants.
    The solution in the third quadrant is x=180∘+54.1∘=234.1∘x = 180^\circ + 54.1^\circ = 234.1^\circ.
    The solution in the fourth quadrant is x=360∘−54.1∘=305.9∘x = 360^\circ - 54.1^\circ = 305.9^\circ.
    The solutions are approximately x=234.1∘,305.9∘\boxed{x = 234.1^\circ, 305.9^\circ}.

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