Calculate the following Using the column method. 1.342×13=. 2. 542×11=. 430×12=. 417×14=.
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15 stepsSet up the multiplication using the column method.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c@{}c@{}c} & 1 & . & 3 & 4 & 2 \\ \times & & & & 1 & 3 \\ \hline \end{array} $$Multiply 1.342 by 3 (the ones digit of 13).
$3 \times 2 = 6$ $3 \times 4 = 12$ (write down 2, carry over 1) $3 \times 3 = 9 + 1 (\text{carry-over}) = 10$ (write down 0, carry over 1) $3 \times 1 = 3 + 1 (\text{carry-over}) = 4$ $$ \begin{array}{@{}c@{\,}c@{}c@{}c@{}c@{}c} & 1 & . & 3 & 4 & 2 \\ \times & & & & 1 & 3 \\ \hline & 4 & . & 0 & 2 & 6 \\ \end{array} $$Multiply 1.342 by 10 (the tens digit of 13).
Add a placeholder zero.
(write down 0, carry over 2)
(write down 2, carry over 4)
(write down 4, carry over 3)
\begin{array}{@{}c@{\,}c@{}c@{}c@{}c@{}c} & 1 & . & 3 & 4 & 2 \\ \times & & & & 1 & 3 \\ \hline & 4 & . & 0 & 2 & 6 \\ 1 & 3 & . & 4 & 2 & 0 \\ \hline \end{array}Add the results from Step 2 and Step 3.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c@{}c@{}c} & 1 & . & 3 & 4 & 2 \\ \times & & & & 1 & 3 \\ \hline & 4 & . & 0 & 2 & 6 \\ + 1 & 3 & . & 4 & 2 & 0 \\ \hline 1 & 7 & . & 4 & 4 & 6 \\ \end{array} $$ The result is **17.446**.2.
Set up the multiplication.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 5 & 4 & 2 \\ \times & & 1 & 1 \\ \hline \end{array} $$Multiply 542 by 1 (the ones digit).
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 5 & 4 & 2 \\ \times & & 1 & 1 \\ \hline & 5 & 4 & 2 \\ \end{array} $$Multiply 542 by 10 (the tens digit).
Add a placeholder zero.
\begin{array}{@{}c@{\,}c@{}c@{}c} & 5 & 4 & 2 \\ \times & & 1 & 1 \\ \hline & 5 & 4 & 2 \\ 5 & 4 & 2 & 0 \\ \hline \end{array}Add the results.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 5 & 4 & 2 \\ \times & & 1 & 1 \\ \hline & 5 & 4 & 2 \\ + 5 & 4 & 2 & 0 \\ \hline 5 & 9 & 6 & 2 \\ \end{array} $$ The result is **5962**.3.
Set up the multiplication.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 3 & 0 \\ \times & & 1 & 2 \\ \hline \end{array} $$Multiply 430 by 2.
$2 \times 0 = 0$ $2 \times 3 = 6$ $2 \times 4 = 8$ $$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 3 & 0 \\ \times & & 1 & 2 \\ \hline & 8 & 6 & 0 \\ \end{array} $$Multiply 430 by 10.
Add a placeholder zero.
(write down 0, carry over 3)
\begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 3 & 0 \\ \times & & 1 & 2 \\ \hline & 8 & 6 & 0 \\ 4 & 3 & 0 & 0 \\ \hline \end{array}Add the results.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 3 & 0 \\ \times & & 1 & 2 \\ \hline & 8 & 6 & 0 \\ + 4 & 3 & 0 & 0 \\ \hline 5 & 1 & 6 & 0 \\ \end{array} $$ The result is **5160**.4.
Set up the multiplication.
$$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 1 & 7 \\ \times & & 1 & 4 \\ \hline \end{array} $$Multiply 417 by 4.
$4 \times 7 = 28$ (write down 8, carry over 2) $4 \times 1 = 4 + 2 (\text{carry-over}) = 6$ $4 \times 4 = 16$ $$ \begin{array}{@{}c@{\,}c@{}c@{}c} & 4 & 1 & 7 \\ \times & & 1 & 4 \\ \hline 1 & 6 & 6 & 8 \\ \end{array} $$Multiply 417 by 10.
Add a placeholder zero.
(write down 0, carry over 7)
(write down 7, carry over 1)
$10 \times 4 = 40
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