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Solve for the perimeter and unknown side length of rectangles given width and length, or perimeter and one side length.

Mathematics

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:
To find the perimeter of a rectangle whose width is 40 cm40 \text{ cm} and length is 60 cm60 \text{ cm}.

  1. Recall the formula for the perimeter of a rectangle.

    The perimeter PP of a rectangle with length ll and width ww is given by:

    P=2(l+w)P = 2(l + w)
  2. Substitute the given values into the formula.

    Given l=60 cml = 60 \text{ cm} and w=40 cmw = 40 \text{ cm}.

    P=2(60 cm+40 cm)P = 2(60 \text{ cm} + 40 \text{ cm})
  3. Perform the addition inside the parentheses.

    P=2(100 cm)P = 2(100 \text{ cm})
  4. Multiply to find the perimeter.

    P=200 cmP = 200 \text{ cm}

    The perimeter of the rectangle is 200 cm\boxed{\text{200 cm}}.

    :
    Find the value of 'L' in the figure below if the perimeter is 140 cm140 \text{ cm}.
    The figure shows a rectangle with one side labeled 'L' and the adjacent side labeled 40 cm40 \text{ cm}.

  5. Recall the formula for the perimeter of a rectangle.

    The perimeter PP of a rectangle with length ll and width ww is given by:

    P=2(l+w)P = 2(l + w)
  6. Identify the given values from the problem and the figure.

    Given perimeter P=140 cmP = 140 \text{ cm}.
    From the figure, one side is LL and the other side is 40 cm40 \text{ cm}. Let l=Ll = L and w=40 cmw = 40 \text{ cm}.

  7. Substitute the known values into the perimeter formula.

    140 cm=2(L+40 cm)140 \text{ cm} = 2(L + 40 \text{ cm})
  8. Divide both sides by 2.

    140 cm2=L+40 cm\frac{140 \text{ cm}}{2} = L + 40 \text{ cm} 70 cm=L+40 cm70 \text{ cm} = L + 40 \text{ cm}
  9. Subtract 40 cm40 \text{ cm} from both sides to solve for LL.

    70 cm−40 cm=L70 \text{ cm} - 40 \text{ cm} = L 30 cm=L30 \text{ cm} = L

    The value of LL is 30 cm\boxed{\text{30 cm}}.

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