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The problem provides the width and length of a rectangle in terms of r, and its perimeter. We need to find the values of the width and length.

Mathematics

ScanSolve AI Answer

Answer

4.4642
7.7320

Step-by-step solution

5 steps

The problem provides the width and length of a rectangle in terms of rr, and its perimeter. We need to find the values of the width and length.

Given:
Width (ww) =r= r
Length (ll) =1.7320r= 1.7320r
Perimeter (PP) =14+10.3923= 14 + 10.3923

  1. Calculate the total perimeter.

    First, sum the given parts of the perimeter.

    P=14+10.3923P = 14 + 10.3923 P=24.3923P = 24.3923
  2. Write the formula for the perimeter of a rectangle.

    The formula for the perimeter of a rectangle is P=2(l+w)P = 2(l + w).

  3. Substitute the given expressions for length and width into the perimeter formula.

    Substitute l=1.7320rl = 1.7320r and w=rw = r into the perimeter formula, and set it equal to the calculated perimeter.

    24.3923=2(1.7320r+r)24.3923 = 2(1.7320r + r)
  4. Solve the equation for rr.

    Combine the terms inside the parenthesis and then solve for rr.

    24.3923=2(2.7320r)24.3923 = 2(2.7320r) 24.3923=5.4640r24.3923 = 5.4640r r=24.39235.4640r = \frac{24.3923}{5.4640} r≈4.4642r \approx 4.4642
  5. Calculate the length and width.

    Now substitute the value of rr back into the expressions for length and width.
    Width:

    w=rw = r w=4.4642w = 4.4642

    Length:

    l=1.7320rl = 1.7320r l=1.7320×4.4642l = 1.7320 \times 4.4642 l≈7.7320l \approx 7.7320

    The width of the rectangle is approximately 4.4642 units and the length is approximately 7.7320 units.

    The width is 4.4642\boxed{4.4642} and the length is 7.7320\boxed{7.7320}.

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