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For what value of c is the expression x2 + 10x + c + 2 a perfect square?

Mathematics

ScanSolve AI Answer

Answer

23

Step-by-step solution

4 steps
  1. Identify the form of a perfect square.

    A quadratic expression in the form x2+Bx+Cx^2 + Bx + C is a perfect square if it can be written as (x+k)2(x+k)^2.
    Expanding (x+k)2(x+k)^2 gives x2+2kx+k2x^2 + 2kx + k^2.

  2. Compare the given expression with the perfect square form.

    The given expression is x2+10x+c+2x^2 + 10x + c + 2.
    Comparing coefficients with x2+2kx+k2x^2 + 2kx + k^2:
    The coefficient of xx is 10, so 2k=102k = 10.
    The constant term is c+2c+2, so k2=c+2k^2 = c+2.

  3. Solve for kk.

    From 2k=102k = 10, we find kk:

    k=102k = \frac{10}{2} k=5k = 5
  4. Solve for cc.

    Substitute the value of kk into the equation for the constant term:

    k2=c+2k^2 = c+2 52=c+25^2 = c+2 25=c+225 = c+2

    Subtract 2 from both sides to find cc:

    c=25−2c = 25 - 2 c=23c = 23

    The value of cc is 23\boxed{23}.

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