Solve for x: 2^x = sqrt(16)

We need to find the square root of 16.

$$\sqrt{16} = 4$$

The equation becomes:

$$2^x = 4$$

We know that 4 can be written as 2 raised to the power of 2.

$$4 = 2^2$$

So, the equation is:

$$2^x = 2^2$$

Since the bases are the same, the exponents must be equal.

$$x = 2$$