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Explain Total Quality Management (TQM). Also explain philosophical elements of TQM in detail.

Computer Science

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Step-by-step solution

9 steps

Part a· 3 steps

Time of flight

  1. Formula for time of flight

    T=2usin⁡θgT = \frac{2 u \sin \theta}{g}
  2. Substitute values (u=10 m/su = 10\ \mathrm{m/s}, θ=30∘\theta = 30^\circ, sin⁡30∘=12\sin 30^\circ = \frac{1}{2}, g=10 m/s2g = 10\ \mathrm{m/s^2})

    T=2×10×1210T = \frac{2 \times 10 \times \frac{1}{2}}{10}
  3. Simplify

    T=1010=1 sT = \frac{10}{10} = 1\ \mathrm{s}

    1 s

Part b· 3 steps

Maximum height

  1. Formula for maximum height

    H=(usin⁡θ)22gH = \frac{(u \sin \theta)^2}{2g}
  2. Substitute values

    H=(10×12)22×10=5220=2520H = \frac{\left(10 \times \frac{1}{2}\right)^2}{2 \times 10} = \frac{5^2}{20} = \frac{25}{20}
  3. Simplify

    H=1.25 mH = 1.25\ \mathrm{m}

    1.25 m

Part c· 3 steps

Range

  1. Formula for range

    R=u2sin⁡2θgR = \frac{u^2 \sin 2\theta}{g}
  2. Substitute values (sin⁡60∘=32\sin 60^\circ = \frac{\sqrt{3}}{2})

    R=102×3210=100×3210=50310R = \frac{10^2 \times \frac{\sqrt{3}}{2}}{10} = \frac{100 \times \frac{\sqrt{3}}{2}}{10} = \frac{50\sqrt{3}}{10}
  3. Simplify

    R=53 mR = 5\sqrt{3}\ \mathrm{m}

    5\sqrt{3} m

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