Explain Total Quality Management (TQM). Also explain philosophical elements of TQM in detail.

Computer Science
Explain Total Quality Management (TQM). Also explain philosophical elements of TQM in detail.

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Answer

1 s

(a): Time of flight

Step 1: Formula for time of flight
T=2usinθgT = \frac{2 u \sin \theta}{g}

Step 2: Substitute values (u=10 m/su = 10\ \mathrm{m/s}, θ=30\theta = 30^\circ, sin30=12\sin 30^\circ = \frac{1}{2}, g=10 m/s2g = 10\ \mathrm{m/s^2})
T=2×10×1210T = \frac{2 \times 10 \times \frac{1}{2}}{10}

Step 3: Simplify
T=1010=1 sT = \frac{10}{10} = 1\ s

1 s

(b): Maximum height

Step 1: Formula for maximum height
H=(usinθ)22gH = \frac{(u \sin \theta)^2}{2g}

Step 2: Substitute values
H=(10×12)22×10=5220=2520H = \frac{\left(10 \times \frac{1}{2}\right)^2}{2 \times 10} = \frac{5^2}{20} = \frac{25}{20}

Step 3: Simplify
H=1.25 mH = 1.25\ m

1.25 m

(c): Range

Step 1: Formula for range
R=u2sin2θgR = \frac{u^2 \sin 2\theta}{g}

Step 2: Substitute values (sin60=32\sin 60^\circ = \frac{\sqrt{3}}{2})
R=102×3210=100×3210=50310R = \frac{10^2 \times \frac{\sqrt{3}}{2}}{10} = \frac{100 \times \frac{\sqrt{3}}{2}}{10} = \frac{50\sqrt{3}}{10}

Step 3: Simplify
R=53 mR = 5\sqrt{3}\ m

5\sqrt{3 m}

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Problem 11(a): Time of flight Step 1: Formula for time of flight T = (2 u )/(g) Step 2: Substitute values (u = 10\ m/s, = 30^, 30^ = (1)/(2), g = 10\ m/s^2) T = (2 × 10 × 1)/(2)10 Step 3: Simplify T = (10)/(10) = 1\ s 1 s Problem 11(b): Maximum height…

Explain Total Quality Management (TQM). Also explain philosophical elements of TQM in detail.
Computer Science

This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.

ScanSolve AI Answer
Problem 11(a): Time of flight Step 1: Formula for time of flight T = (2 u )/(g) Step 2: Substitute values (u = 10\ m/s, = 30^, 30^ = (1)/(2), g = 10\ m/s^2) T = (2 × 10 × 1)/(2)10 Step 3: Simplify T = (10)/(10) = 1\ s 1 s Problem 11(b): Maximum height Step 1: Formula for maximum height H = ((u )^2)/(2g) Step 2: Substitute values H = ((10 × 1)/(2))^22 × 10 = (5^2)/(20) = (25)/(20) Step 3: Simplify H = 1.25\ m 1.25 m Problem 11(c): Range Step 1: Formula for range R = (u^2 2)/(g) Step 2: Substitute values ( 60^ = sqrt(3)2) R = 10^2 × sqrt(3)210 = 100 × sqrt(3)210 = 50sqrt(3)10 Step 3: Simplify R = 5sqrt(3)\ m 5sqrt(3) m