Given cosh x = 1/2(e^x + e^-x) and sinh x = 1/2(e^x - e^-x), Use these definitions to show cosh2 x - sinh2 x = 1, Show that cosh x + sinh x = e^x and simplify cosh x - sinh x.

Given $y = 3x^2 + 2x - 4$.

$$\frac{dy}{dx} = \frac{d}{dx}(3x^2 + 2x - 4) = 6x + 2$$

The initial value of $x$ is 2.
The change in $x$, denoted as $\Delta x$, is the difference between the new value and the initial value:

$$\Delta x = 2.02 - 2 = 0.02$$

Substitute $x = 2$ into the derivative:

$$\frac{dy}{dx} \Big|_{x=2} = 6(2) + 2 = 12 + 2 = 14$$

The small change in $y$, denoted as $\Delta y$, is approximately given by $\Delta y \approx \frac{dy}{dx} \Delta x$.

$$\Delta y \approx 14 \times 0.02 = 0.28$$

The small change in $y$ is $\boxed{\text{0.28}}$.