Given: P2 = 48 W, V2 = 32 V.

Step 1: Define power.
Power is the rate at which electrical energy is transferred or converted from one form to another.

Step 2: Calculate the reading on ammeter $A_2$.
Bulb $L_2$ operates at its rated power and voltage.
Given: $P_2 = 48 \, \text{W}$, $V_2 = 32 \, \text{V}$.
The current through $L_2$ is measured by ammeter $A_2$.

$$I_{A2} = \frac{P_2}{V_2}$$ $$I_{A2} = \frac{48 \, \text{W}}{32 \, \text{V}}$$ $$$$