Define the given quantities and set up the coordinate system.

To find the point where the total electric field is zero, we need to find a location where the electric fields due to q_1 and q_2 are equal in magnitude and opposite in direction. Since both charges are positive, this point must lie between the two charges. Step 1: Define the given quantities and set up the coordinate system. Let q_1 = 0.700 nc = 0.700 × 10^-9 C and q_2 = 9.00 nc = 9.00 × 10^-9 C. The distance between the charges is d = 1.40 m. Let q_1 be at the origin (x=0) and q_2 be at x=d. Let the point where the electric field is zero be at a distance x from q_1. The distance from q_2 to this point will then be d-x. Step 2: State the condition for the total electric field to be zero. The magnitude of the electric field due to a point charge q at a distance r is given by E = k (|q|)/(r^2), where k is Coulomb's constant. For the total electric field to be zero at point x, the electric field due to q_1 (E_1) must be equal in magnitude to the electric field due to q_2 (E_2). E_1 = E_2 Step 3: Write the expressions for E_1 and E_2 and set them equal. k (q_1)/(x^2) = k (q_2)/((d-x)^2) We can cancel k from both sides: (q_1)/(x^2) = (q_2)/((d-x)^2) Step 4: Substitute the given values and solve for x. 0.700 × 10^-9 Cx^2 = 9.00 × 10^-9 C(1.40 m - x)^2 Cancel 10^-9 from both sides: (0.700)/(x^2) = (9.00)/((1.40 - x)^2) Take the square root of both sides: sqrt((0.700)/(x^2)) = sqrt((9.00)/((1.40 - x)^2)) sqrt(0.700)x = sqrt(9.00)1.40 - x (0.83666)/(x) = (3)/(1.40 - x) Cross-multiply: 0.83666 (1.40 - x) = 3x 1.171324 - 0.83666x = 3x 1.171324 = 3x + 0.83666x 1.171324 = 3.83666x x = (1.171324)/(3.83666) x ≈ 0.305309 m Step 5: State the final answer. Rounding to three significant figures, the point where the total electric field is zero is: x = 0.305 m from q_1 That's 2 down. 3 left today — send the next one.