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Given the function y = 2x5 + 4x4 - x3 + 3x2 - 5x + 7, find the value of dy/dx when x=2.

Mathematics

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Answer

283\text{283}

Graph of y = 2x⁵ + 4x⁴ − x³ + 3x² − 5x + 7

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Key points of y = 2x⁵ + 4x⁴ − x³ + 3x² − 5x + 7
Pointxy
x-intercept−2.620
Maximum−1.9737.04
y-intercept07
Minimum0.515.44

Step-by-step solution

5 steps
  1. The given function is

    y=2x5+4x4−x3+3x2−5x+7y = 2x^5 + 4x^4 - x^3 + 3x^2 - 5x + 7
  2. Differentiate each term of the polynomial with respect to xx using the power rule ddx(axn)=anxn−1\frac{d}{dx}(ax^n) = anx^{n-1} and the rule that the derivative of a constant is 0.

    dydx=ddx(2x5)+ddx(4x4)−ddx(x3)+ddx(3x2)−ddx(5x)+ddx(7)\frac{dy}{dx} = \frac{d}{dx}(2x^5) + \frac{d}{dx}(4x^4) - \frac{d}{dx}(x^3) + \frac{d}{dx}(3x^2) - \frac{d}{dx}(5x) + \frac{d}{dx}(7) dydx=(2⋅5)x5−1+(4⋅4)x4−1−(1⋅3)x3−1+(3⋅2)x2−1−(5⋅1)x1−1+0\frac{dy}{dx} = (2 \cdot 5)x^{5-1} + (4 \cdot 4)x^{4-1} - (1 \cdot 3)x^{3-1} + (3 \cdot 2)x^{2-1} - (5 \cdot 1)x^{1-1} + 0
  3. Simplify the expression for dydx\frac{dy}{dx}.

    dydx=10x4+16x3−3x2+6x−5\frac{dy}{dx} = 10x^4 + 16x^3 - 3x^2 + 6x - 5
  4. Substitute x=2x=2 into the expression for dydx\frac{dy}{dx} to find its value.

    dydx∣x=2=10(2)4+16(2)3−3(2)2+6(2)−5\frac{dy}{dx} \Big|_{x=2} = 10(2)^4 + 16(2)^3 - 3(2)^2 + 6(2) - 5 dydx∣x=2=10(16)+16(8)−3(4)+12−5\frac{dy}{dx} \Big|_{x=2} = 10(16) + 16(8) - 3(4) + 12 - 5 dydx∣x=2=160+128−12+12−5\frac{dy}{dx} \Big|_{x=2} = 160 + 128 - 12 + 12 - 5
  5. Perform the arithmetic operations.

    dydx∣x=2=288−12+12−5\frac{dy}{dx} \Big|_{x=2} = 288 - 12 + 12 - 5 dydx∣x=2=276+12−5\frac{dy}{dx} \Big|_{x=2} = 276 + 12 - 5 dydx∣x=2=288−5\frac{dy}{dx} \Big|_{x=2} = 288 - 5 dydx∣x=2=283\frac{dy}{dx} \Big|_{x=2} = \boxed{\text{283}}
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