Given the relation y = ax^n, how do you find the constants a and n using logarithms?

April 13, 2026Mathematics

ScanSolve AI Answer

April 13, 2026

Answer

ax^n$$

To find the constants $a$ and $n$ from the relation $y = ax^n$ , we first linearize the equation by taking the logarithm of both sides. Using $\log_{10}$ :

Step 1: Linearize the equation. $y = ax^n$ $\log_{10} y = \log_{10} (ax^n)$ $\log_{10} y = \log_{10} a + \log_{10} (x^n)$ $\log_{10} y = n \log_{10} x + \log_{10} a$ This equation is in the form $Y = mX + C$ , where $Y = \log_{10} y$ , $X =

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Quick Answer

To find the constants a and n from the relation y = ax^n, we first linearize the equation by taking the logarithm of both sides.

Asked on April 13, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 13, 2026

To find the constants a and n from the relation y = ax^n, we first linearize the equation by taking the logarithm of both sides. Using _10: Step 1: Linearize the equation. y = ax^n _10 y = _10 (ax^n) _10 y = _10 a + _10 (x^n) _10 y = n _10 x + _10 a This equation is in the form Y = mX + C, where Y = _10 y, $X =