Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2), Bottom right C = 1(1)/(3).

The pattern in these problems is that the top number (in the square) is the difference between the two bottom numbers (in the circles). That is, if the top number is A and the bottom numbers are B and C, then A = |B − C|. Let's solve each problem: 1. Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2), Bottom right C = 1(1)/(3). We need to find the missing value, which is the top number. The top number is given as 1(1)/(6). The bottom numbers are $

Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2), Bottom right C = 1(1)/(3).

The pattern in these problems is that the top number (in the square) is the difference between the two bottom numbers (in the circles). That is, if the top number is A and the bottom numbers are B and C, then A = |B − C|. Let's solve each problem: 1. Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2), Bottom right C = 1(1)/(3). We need to find the missing value, which is the top number. The top number is given as 1(1)/(6). The bottom numbers are $

Solved: Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2)…

Let's solve each problem:

1.
Given: Top $A = 1\frac{1}{6}$ , Bottom left $B = 2\frac{1}{2}$ , Bottom right $C = 1\frac{1}{3}$ .
We need to find the missing value, which is the top number.
The top number is given as $1\frac{1}{6}$ . The bottom numbers are $

Given: Top A = 1(1)/(6), Bottom left B = 2(1)/(2), Bottom right C = 1(1)/(3).

Answer

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