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Graph the linear equation 2x + y − 1 = 0, find its x-intercept and y-intercept.

Mathematics

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Answer

(12,0)\left(\frac{1}{2}, 0\right)

(0, 1)
Graph of y = −2x + 1

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of y = −2x + 1
Pointxy
y-intercept01
x-intercept0.50

Step-by-step solution

4 steps

Here's the solution for .6, Question 1:

The equation given is 2x+y−1=02x + y - 1 = 0.

  1. Rearrange the equation to solve for yy.

    y=−2x+1y = -2x + 1
  2. Create a table of values by choosing several xx-values and calculating the corresponding yy-values.

    xxy=−2x+1y = -2x + 1(x,y)(x, y)
    -1y=−2(−1)+1=2+1=3y = -2(-1) + 1 = 2 + 1 = 3(−1,3)(-1, 3)
    0y=−2(0)+1=0+1=1y = -2(0) + 1 = 0 + 1 = 1(0,1)(0, 1)
    1y=−2(1)+1=−2+1=−1y = -2(1) + 1 = -2 + 1 = -1(1,−1)(1, -1)
    2y=−2(2)+1=−4+1=−3y = -2(2) + 1 = -4 + 1 = -3(2,−3)(2, -3)
  3. Determine the x-intercept.

    The x-intercept is the point where the graph crosses the x-axis, meaning y=0y = 0.

    0=−2x+10 = -2x + 1 2x=12x = 1 x=12x = \frac{1}{2}

    The x-intercept is (12,0)\boxed{\left(\frac{1}{2}, 0\right)}.

  4. Determine the y-intercept.

    The y-intercept is the point where the graph crosses the y-axis, meaning x=0x = 0.

    y=−2(0)+1y = -2(0) + 1 y=1y = 1

    The y-intercept is (0,1)\boxed{(0, 1)}.

    To draw the graph, plot the points from the table of values, including the x-intercept and y-intercept, and then draw a straight line through them.

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