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Identify the given matrix A.

Mathematics

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Answer

22

Step-by-step solution

5 steps
  1. Identify the given matrix A.

    The matrix A is a 3×33 \times 3 matrix:

    A=∣−2312−13121∣A = \begin{vmatrix} -2 & 3 & 1 \\ 2 & -1 & 3 \\ 1 & 2 & 1 \end{vmatrix}
  2. Calculate the determinant using cofactor expansion along the first row.

    The formula for the determinant of a 3×33 \times 3 matrix ∣abcdefghi∣\begin{vmatrix} a & b & c \\ d & e & f \\ g & h & i \end{vmatrix} is a(ei−fh)−b(di−fg)+c(dh−eg)a(ei - fh) - b(di - fg) + c(dh - eg).

  3. Substitute the values from matrix A into the determinant formula.

    det⁡(A)=−2∣−1321∣−3∣2311∣+1∣2−112∣\det(A) = -2 \begin{vmatrix} -1 & 3 \\ 2 & 1 \end{vmatrix} - 3 \begin{vmatrix} 2 & 3 \\ 1 & 1 \end{vmatrix} + 1 \begin{vmatrix} 2 & -1 \\ 1 & 2 \end{vmatrix}
  4. Calculate the 2×22 \times 2 determinants.

    ∣−1321∣=(−1)(1)−(3)(2)=−1−6=−7\begin{vmatrix} -1 & 3 \\ 2 & 1 \end{vmatrix} = (-1)(1) - (3)(2) = -1 - 6 = -7 ∣2311∣=(2)(1)−(3)(1)=2−3=−1\begin{vmatrix} 2 & 3 \\ 1 & 1 \end{vmatrix} = (2)(1) - (3)(1) = 2 - 3 = -1 ∣2−112∣=(2)(2)−(−1)(1)=4−(−1)=4+1=5\begin{vmatrix} 2 & -1 \\ 1 & 2 \end{vmatrix} = (2)(2) - (-1)(1) = 4 - (-1) = 4 + 1 = 5
  5. Substitute these values back into the expression for det⁡(A)\det(A) and simplify.

    det⁡(A)=−2(−7)−3(−1)+1(5)\det(A) = -2(-7) - 3(-1) + 1(5) det⁡(A)=14+3+5\det(A) = 14 + 3 + 5 det⁡(A)=22\det(A) = 22

    The final answer is 22.

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