Solved: If ACE = 15 and BDF = 48, what is the value of HJL?

Determine the numerical position of each letter in the alphabet (A=1, B=2, C=3, and so on).
For ACE = 15:
A = 1
C = 3
E = 5
Multiplying these positions: $1 \times 3 \times 5 = 15$ . This matches the given value.
Verify the rule with BDF = 48.
B = 2
D = 4
F = 6
Multiplying these positions: $2 \times 4 \times 6 = 48$ . This also matches the given value.
Apply the established rule to HJL.
H = 8
J = 10
L = 12
Multiply their alphabetical positions:
$8 \times 10 \times 12 = 80 \times 12 = 960$
Therefore, HJL = 960.

The final answer is $\text{960}$ .

If ACE = 15 and BDF = 48, what is the value of HJL?