Initial height of tower, h0 = 50 m

Here are the calculations for the stone's motion: Given: Initial height of tower, h_0 = 50 m Initial velocity, u = 20 m/s (upwards) Acceleration due to gravity, g = 10 m/s^2 i) The maximum height reached from the ground. Step 1: Calculate the height gained by the stone above the tower. At maximum height, the final velocity v = 0 m/s. We use the kinematic equation v^2 = u^2 + 2as. Here, a = -g because gravity acts downwards, opposite to the initial upward motion. 0^2 = (20 m/s)^2 + 2(-10 m/s^2)s 0 = 400 m^2/s^2 - 20 m/s^2 · s 20 m/s^2 · s = 400 m^2/s^2 s = 400 m^2/s^220 m/s^2 = 20 m This is the height reached above the tower. Step 2: Calculate the maximum height from the ground. The maximum height from the ground is the initial height of the tower plus the height gained above the tower. H_max = h_0 + s H_max = 50 m + 20 m = 70 m The maximum height reached from the ground is 70 m. ii) The time it takes to reach the maximum height. Step 1: Calculate the time to reach maximum height. We use the kinematic equation v = u + at. Here, v = 0 m/s, u = 20 m/s, and a = -g = -10 m/s^2. 0 = 20 m/s + (-10 m/s^2)t 10 m/s^2 · t = 20 m/s t = 20 m/s10 m/s^2 = 2 s The time it takes to reach the maximum height is 2 s. iii) The total distance covered. Step 1: Calculate the distance covered during the upward motion. This is the height gained above the tower, which was calculated in part (i). Distance upward = 20 m. Step 2: Calculate the distance covered during the downward motion. The stone falls from its maximum height (70 m from the ground) to the ground. Distance downward = H_max = 70 m. Step 3: Calculate the total distance covered. Total distance = Distance upward + Distance downward Total distance = 20 m + 70 m = 90 m The total distance covered is 90 m. Send me the next one 📸