A²+81-18²/4(a+3)²

Mathematics

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Answer

a2a^{2}

Step-by-step solution

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समस्या:

a2+81−1824(a+3)2a^{2} + 81 - \frac{18^{2}}{4(a + 3)^{2}}

  1. पहिलो, 18218^{2} र 4(a+3)24(a + 3)^{2} को मान निकालौं।

    182=32418^{2} = 324

  2. अब, 4(a+3)24(a + 3)^{2} को मान निकालौं।

    4(a+3)2=4(a2+6a+9)=4a2+24a+364(a + 3)^{2} = 4(a^{2} + 6a + 9) = 4a^{2} + 24a + 36

  3. अब, मूल समीकरणमा मानहरू राखौं।

    a2+81−3244(a+3)2a^{2} + 81 - \frac{324}{4(a + 3)^{2}}

  4. 3244\frac{324}{4} लाई सरल बनाउँदा,

    3244=81\frac{324}{4} = 81

  5. अब, समीकरणलाई पुनः लेखौं।

    a2+81−81a^{2} + 81 - 81

  6. यसलाई सरल बनाउँदा,

    a2a^{2}

    अन्तिम उत्तर:

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