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Find the level curves f(x, y) = c for the given functions and values of c. Describe their shapes.

Mathematics

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Step-by-step solution

7 steps

To find the level curves f(x,y)=cf(x, y) = c, we set the given function equal to each value of cc and simplify the resulting equation. Since I am a text-based AI, I will provide the equations for the level curves and describe their shapes, but I cannot sketch them.

13. f(x,y)=x+y−1f(x, y) = x + y - 1, c=−3,−2,−1,0,1,2,3c = -3, -2, -1, 0, 1, 2, 3

  1. Set f(x,y)=cf(x, y) = c.

    x+y−1=cx + y - 1 = c
  2. Rearrange the equation to solve for yy.

    y=−x+1+cy = -x + 1 + c

    These are equations of parallel lines with a slope of −1-1.

    • For c=−3c = -3: y=−x+1−3⇒y=−x−2y = -x + 1 - 3 \Rightarrow \boxed{y = -x - 2}
    • For c=−2c = -2: y=−x+1−2⇒y=−x−1y = -x + 1 - 2 \Rightarrow \boxed{y = -x - 1}
    • For c=−1c = -1: y=−x+1−1⇒y=−xy = -x + 1 - 1 \Rightarrow \boxed{y = -x}
    • For c=0c = 0: y=−x+1+0⇒y=−x+1y = -x + 1 + 0 \Rightarrow \boxed{y = -x + 1}
    • For c=1c = 1: y=−x+1+1⇒y=−x+2y = -x + 1 + 1 \Rightarrow \boxed{y = -x + 2}
    • For c=2c = 2: y=−x+1+2⇒y=−x+3y = -x + 1 + 2 \Rightarrow \boxed{y = -x + 3}
    • For c=3c = 3: y=−x+1+3⇒y=−x+4y = -x + 1 + 3 \Rightarrow \boxed{y = -x + 4}

    14. f(x,y)=x2+4y2f(x, y) = x^2 + 4y^2, c=0,1,4,9,16,25c = 0, 1, 4, 9, 16, 25

  3. Set f(x,y)=cf(x, y) = c.

    x2+4y2=cx^2 + 4y^2 = c

    These are equations of ellipses centered at the origin, or a point if c=0c=0.

    • For c=0c = 0: x2+4y2=0⇒x=0,y=0x^2 + 4y^2 = 0 \Rightarrow \boxed{x=0, y=0} (a single point at the origin)
    • For c=1c = 1: x2+4y2=1⇒x21+y21/4=1x^2 + 4y^2 = 1 \Rightarrow \boxed{\frac{x^2}{1} + \frac{y^2}{1/4} = 1} (an ellipse with semi-axes a=1,b=1/2a=1, b=1/2)
    • For c=4c = 4: x2+4y2=4⇒x24+y21=1x^2 + 4y^2 = 4 \Rightarrow \boxed{\frac{x^2}{4} + \frac{y^2}{1} = 1} (an ellipse with semi-axes a=2,b=1a=2, b=1)
    • For c=9c = 9: x2+4y2=9⇒x29+y29/4=1x^2 + 4y^2 = 9 \Rightarrow \boxed{\frac{x^2}{9} + \frac{y^2}{9/4} = 1} (an ellipse with semi-axes a=3,b=3/2a=3, b=3/2)
    • For c=16c = 16: x2+4y2=16⇒x216+y24=1x^2 + 4y^2 = 16 \Rightarrow \boxed{\frac{x^2}{16} + \frac{y^2}{4} = 1} (an ellipse with semi-axes a=4,b=2a=4, b=2)
    • For c=25c = 25: x2+4y2=25⇒x225+y225/4=1x^2 + 4y^2 = 25 \Rightarrow \boxed{\frac{x^2}{25} + \frac{y^2}{25/4} = 1} (an ellipse with semi-axes a=5,b=5/2a=5, b=5/2)

    15. f(x,y)=xyf(x, y) = xy, c=−3,−2,−1,0,1,2,3c = -3, -2, -1, 0, 1, 2, 3

  4. Set f(x,y)=cf(x, y) = c.

    xy=cxy = c

    These are equations of hyperbolas, except for c=0c=0.

    • For c=−3c = -3: xy=−3\boxed{xy = -3} (a hyperbola in the second and fourth quadrants)
    • For c=−2c = -2: xy=−2\boxed{xy = -2} (a hyperbola in the second and fourth quadrants)
    • For c=−1c = -1: xy=−1\boxed{xy = -1} (a hyperbola in the second and fourth quadrants)
    • For c=0c = 0: xy=0\boxed{xy = 0} (the x-axis and y-axis)
    • For c=1c = 1: xy=1\boxed{xy = 1} (a hyperbola in the first and third quadrants)
    • For c=2c = 2: xy=2\boxed{xy = 2} (a hyperbola in the first and third quadrants)
    • For c=3c = 3: xy=3\boxed{xy = 3} (a hyperbola in the first and third quadrants)

    16. f(x,y)=25−x2−y2f(x, y) = \sqrt{25 - x^2 - y^2}, c=0,1,2,3,4c = 0, 1, 2, 3, 4

  5. Set f(x,y)=cf(x, y) = c.

    25−x2−y2=c\sqrt{25 - x^2 - y^2} = c
  6. Square both sides of the equation.

    Note that cc must be non-negative.

    25−x2−y2=c225 - x^2 - y^2 = c^2
  7. Rearrange the equation to the standard form of a circle.

    x2+y2=25−c2x^2 + y^2 = 25 - c^2

    These are equations of concentric circles centered at the origin.

    • For c=0c = 0: x2+y2=25−02⇒x2+y2=25x^2 + y^2 = 25 - 0^2 \Rightarrow \boxed{x^2 + y^2 = 25} (a circle with radius 5)
    • For c=1c = 1: x2+y2=25−12⇒x2+y2=24x^2 + y^2 = 25 - 1^2 \Rightarrow \boxed{x^2 + y^2 = 24} (a circle with radius 24=26\sqrt{24} = 2\sqrt{6})
    • For c=2c = 2: x2+y2=25−22⇒x2+y2=21x^2 + y^2 = 25 - 2^2 \Rightarrow \boxed{x^2 + y^2 = 21} (a circle with radius 21\sqrt{21})
    • For c=3c = 3: x2+y2=25−32⇒x2+y2=16x^2 + y^2 = 25 - 3^2 \Rightarrow \boxed{x^2 + y^2 = 16} (a circle with radius 4)
    • For c=4c = 4: x2+y2=25−42⇒x2+y2=9x^2 + y^2 = 25 - 4^2 \Rightarrow \boxed{x^2 + y^2 = 9} (a circle with radius 3)
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