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Find the missing angles x, y, and k in the given triangles.

Mathematics

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Step-by-step solution

17 steps

Here are the solutions for the marked angles:

  1. : The triangle is a right-angled triangle, so one angle is 90∘90^\circ. The sum of angles in a triangle is 180∘180^\circ.
  1. Set up the equation for the sum of angles.

    $$
    x + 90^\circ + 40^\circ = 180^\circ
    $$
    
  2. Combine the known angles.

    $$
    x + 130^\circ = 180^\circ
    $$
    
  3. Solve for xx.

    $$
    x = 180^\circ - 130^\circ
    $$
    $$
    x = 50^\circ
    $$
    The value of $x$ is $\boxed{\text{50}^\circ}$.
    

    2. : The markings indicate that it is an isosceles triangle, meaning the two base angles are equal. One base angle is 50∘50^\circ, so the other base angle is also 50∘50^\circ. The sum of angles in a triangle is 180∘180^\circ.

  4. Set up the equation for the sum of angles.

    $$
    y + 50^\circ + 50^\circ = 180^\circ
    $$
    
  5. Combine the known angles.

    $$
    y + 100^\circ = 180^\circ
    $$
    
  6. Solve for yy.

    $$
    y = 180^\circ - 100^\circ
    $$
    $$
    y = 80^\circ
    $$
    The value of $y$ is $\boxed{\text{80}^\circ}$.
    

    3. : The markings indicate that all three sides of the triangle are equal, making it an equilateral triangle. All angles in an equilateral triangle are equal. The sum of angles in a triangle is 180∘180^\circ.

  7. Divide the total angle sum by 3.

    $$
    k = \frac{180^\circ}{3}
    $$
    
  8. Calculate the value of kk.

    $$
    k = 60^\circ
    $$
    The value of $k$ is $\boxed{\text{60}^\circ}$.
    

    4. : The markings indicate that two sides of the triangle are equal, making it an isosceles triangle. The angles opposite the equal sides are equal.

  9. Set the angles opposite the equal sides equal to each other.

    $$
    2a = 62^\circ
    $$
    
  10. Solve for aa.

    $$
    a = \frac{62^\circ}{2}
    $$
    $$
    a = 31^\circ
    $$
    The value of $a$ is $\boxed{\text{31}^\circ}$.
    

    5. : The markings indicate that sides AB and AC are equal, making it an isosceles triangle. The exterior angle at B is 108∘108^\circ.

  11. Find the interior angle at B.

    Angles on a straight line sum to 180∘180^\circ. ∠ABC=180∘−108∘=72∘ \angle ABC = 180^\circ - 108^\circ = 72^\circ

  12. Since AB = AC, the base angles opposite these sides are equal.

    $$
    \angle ACB = \angle ABC = 72^\circ
    $$
    
  13. The sum of angles in triangle ABC is 180∘180^\circ.

    Set up the equation for the sum of angles. y+72∘+72∘=180∘ y + 72^\circ + 72^\circ = 180^\circ

  14. Combine the known angles and solve for yy.

    $$
    y + 144^\circ = 180^\circ
    $$
    $$
    y = 180^\circ - 144^\circ
    $$
    $$
    y = 36^\circ
    $$
    The value of $y$ is $\boxed{\text{36}^\circ}$.
    

    6. : The triangle is a right-angled triangle, so one angle is 90∘90^\circ. The sum of angles in a triangle is 180∘180^\circ.

  15. Set up the equation for the sum of angles.

    $$
    90^\circ + 65^\circ + \text{marked angle} = 180^\circ
    $$
    
  16. Combine the known angles.

    $$
    155^\circ + \text{marked angle} = 180^\circ
    $$
    
  17. Solve for the marked angle.

    $$
    \text{marked angle} = 180^\circ - 155^\circ
    $$
    $$
    \text{marked angle} = 25^\circ
    $$
    The value of the marked angle is $\boxed{\text{25}^\circ}$.
    
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