This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Here are the solutions to questions 44 to 47. 44. Observe the bar graph carefully and answer the given questions: From the bar graph, the heights of the mountain peaks are: Kanchenjunga: 8500 m Nanda Devi: 7800 m Mount Everest: 8800 m Himadri: 7800 m Nanga Parbat: 8100 m a)* What information is given by the bar graph? The bar graph shows the Heights of Mountain Peaks. b)* Name the lowest of the given peaks and what is its height. The lowest height is 7800 m. The lowest peaks are Nanda Devi and Himadri, with a height of 7800 m. c)* Find the ratio of the heights of the lowest and highest peaks. Lowest height = 7800 m Highest height (Mount Everest) = 8800 m Ratio = Lowest heightHighest height 7800 m8800 m = (78)/(88) = (39)/(44) The ratio is 39:44. d)* Write down the measurement of the heights of the peaks in the ascending order. The heights in ascending order are: Himadri (7800 m), Nanda Devi (7800 m), Nanga Parbat (8100 m), Kanchenjunga (8500 m), Mount Everest (8800 m). 45. Charu runs around a square park of sides 85 m. Pooja runs around a rectangular park of length 70 m and breadth 55 m. Who covers less distance? Step 1: Calculate the distance covered by Charu. Charu runs around a square park with side 85 m. Distance covered by Charu = Perimeter of square P_Charu = 4 × side = 4 × 85 m = 340 m Step 2: Calculate the distance covered by Pooja. Pooja runs around a rectangular park with length 70 m and breadth 55 m. Distance covered by Pooja = Perimeter of rectangle P_Pooja = 2 × (length + breadth) = 2 × (70 m + 55 m) P_Pooja = 2 × (125 m) = 250 m Step 3: Compare the distances. Charu's distance = 340 m Pooja's distance = 250 m Since 250 m < 340 m, Pooja covers less distance. Pooja covers less distance. 46. Diameter of a sphere is 9 cm. What is its radius? Step 1: Use the formula relating diameter and radius. The radius is half of the diameter. Radius = Diameter2 Step 2: Substitute the given diameter. Radius = 9 cm2 = 4.5 cm The radius is 4.5 cm. 47. How many tiles whose length and breadth are 12 cm and 5 cm respectively will fit in a rectangular region whose length and breadth are 100 cm and 144 cm? Step 1: Calculate the area of one tile. Length of tile = 12 cm Breadth of tile = 5 cm Area of one tile = 12 cm × 5 cm = 60 cm^2 Step 2: Calculate the area of the rectangular region. Length of region = 100 cm Breadth of region = 144 cm Area of rectangular region = 100 cm × 144 cm = 14400 cm^2 Step 3: Calculate the number of tiles. Number of tiles = Area of rectangular regionArea of one tile Number of tiles = 14400 cm^260 cm^2 = 240 The number of tiles is 240. 3 done, 2 left today. You're making progress.