Calculate the radius of the cylindrical tank.

Here are the solutions to the problems. Problem 1: Cylindrical and Rectangular Tank Step 1: Calculate the radius of the cylindrical tank. The diameter is 5.6 m, so the radius r is half of the diameter. r = 5.6 m2 = 2.8 m Step 2: Calculate the volume of water in the cylindrical tank. The formula for the volume of a cylinder is V = r^2 h. Given h_c = 2.5 m. We will use = (22)/(7). V_c = (2.8 m)^2 (2.5 m) V_c = (22)/(7) × (2.8 m) × (2.8 m) × (2.5 m) V_c = 22 × (0.4 m) × (2.8 m) × (2.5 m) V_c = 8.8 m × 2.8 m × 2.5 m V_c = 24.64 m^2 × 2.5 m V_c = 61.6 m^3 Step 3: Set up the equation for the volume of water in the rectangular tank. The volume of water transferred to the rectangular tank is the same as the volume in the cylindrical tank. The formula for the volume of a rectangular tank is V = L × W × h. Given L = 5.5 m and W = 4 m. Let h_r be the height of the water in the rectangular tank. V_r = (5.5 m) × (4 m) × h_r V_r = 22 h_r m^2 Step 4: Solve for the height of the water in the rectangular tank. Since V_c = V_r: 61.6 m^3 = 22 h_r m^2 h_r = 61.6 m^322 m^2 h_r = 2.8 m The height of the water in the rectangular tank was 2.8 m. Problem 2: Half Marathon Speed Step 1: Convert the distance from kilometers to meters. The race is 21 km long. 1 km = 1000 m D = 21 km × 1000 m1 km = 21000 m Step 2: Convert the time from hours and minutes to seconds. Peter ran the race in 1 hour 40 minutes. 1 hour = 60 minutes Total minutes = 60 minutes + 40 minutes = 100 minutes 1 minute = 60 seconds Total seconds = 100 minutes × 60 seconds1 minute = 6000 seconds Step 3: Calculate Peter's speed in meters per second. The formula for speed is S = (D)/(T). S = 21000 m6000 s S = (21)/(6) m/s S = 3.5 m/s Peter's speed was 3.5 m/s. That's 2 down. 3 left today — send the next one.