This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Here's how to construct the plain scale:
A plain scale is used to represent two consecutive units (e.g., yards and feet, or meters and decimeters).
Step 1: Calculate the Representative Fraction (RF). The scale is given as 1 foot (actual length) = 1.5 inches (drawing length). We need to express both in the same units to find the RF. We know that 1 foot = 12 inches.
The Representative Fraction is .
Step 2: Determine the Length of the Scale (LOS). The scale needs to be long enough to measure up to 4 feet and read yards and feet. Since 1 yard = 3 feet, 4 feet is 1 yard and 1 foot. To have clear yard divisions, it's practical to make the total length of the scale represent a whole number of yards that covers 4 feet. The smallest such whole number is 2 yards (which is 6 feet).
Convert 2 yards to inches: 2 yards = 2 3 feet = 6 feet = 6 12 inches = 72 inches. The total length of the scale to be drawn is .
Step 3: Construct the Scale.
Step 4: Divide into Primary Divisions (Yards).
Step 5: Divide the Leftmost Primary Division into Secondary Divisions (Feet).
Step 6: Final Touches.
Here is a conceptual diagram of the constructed scale:
<----------------------------------------------------------------------------------------------------->
| 1 ft | 1 ft | 1 ft | 1 yard |
| | | | |
<----------------------------------------------------------------------------------------------------->
3 2 1 0 1 YARD
(FEET) (YARDS)
RF = 1:8
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Here's how to construct the plain scale: A plain scale is used to represent two consecutive units (e.g., yards and feet, or meters and decimeters).
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.