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Find sample standard deviation S.D.

Mathematics

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Answer

s≈259.76s \approx 259.76

Step-by-step solution

5 steps

To calculate the sample standard deviation (S.D.) for grouped data, we use the formula:

s=∑fi(xi−xˉ)2N−1s = \sqrt{\frac{\sum f_i (x_i - \bar{x})^2}{N-1}}

where:

  • ss is the sample standard deviation
  • fif_i is the frequency of each class
  • xix_i is the midpoint of each class
  • xˉ\bar{x} is the sample mean
  • NN is the total number of observations (∑fi\sum f_i)

First, we need to determine the midpoints (xix_i) for each class. Given the classes "700-799" and "800-899", we assume a consistent class width of 100 for the other single-value classes (e.g., "900" means "900-999").

Here is the table with midpoints and calculations:

ClassFrequency (fif_i)Midpoint (xix_i)fixif_i x_i(xi−xˉ)(x_i - \bar{x})(xi−xˉ)2(x_i - \bar{x})^2fi(xi−xˉ)2f_i (x_i - \bar{x})^2
700-7994749.52998-5002500001000000
800-8997849.55946.5-4001600001120000
900-9998949.57596-30090000720000
1000-1099101049.510495-20040000400000
1100-1199121149.513794-10010000120000
1200-1299171249.521241.5000
1300-1399131349.517543.510010000130000
1400-1499101449.51449520040000400000
1500-159991549.513945.530090000810000
1600-169971649.511546.54001600001120000
1700-179921749.53499500250000500000
1800-189911849.51849.5600360000360000
Total1001249506680000
  1. Calculate the total number of observations (NN).

    N=∑fi=4+7+8+10+12+17+13+10+9+7+2+1=100N = \sum f_i = 4+7+8+10+12+17+13+10+9+7+2+1 = 100
  2. Calculate the sum of fixif_i x_i.

    ∑fixi=2998+5946.5+7596+10495+13794+21241.5+17543.5+14495+13945.5+11546.5+3499+1849.5=124950\sum f_i x_i = 2998 + 5946.5 + 7596 + 10495 + 13794 + 21241.5 + 17543.5 + 14495 + 13945.5 + 11546.5 + 3499 + 1849.5 = 124950
  3. Calculate the sample mean (xˉ\bar{x}).

    xˉ=∑fixiN=124950100=1249.5\bar{x} = \frac{\sum f_i x_i}{N} = \frac{124950}{100} = 1249.5
  4. Calculate the sum of fi(xi−xˉ)2f_i (x_i - \bar{x})^2.

    ∑fi(xi−xˉ)2=1000000+1120000+720000+400000+120000+0+130000+400000+810000+1120000+500000+360000=6680000\sum f_i (x_i - \bar{x})^2 = 1000000 + 1120000 + 720000 + 400000 + 120000 + 0 + 130000 + 400000 + 810000 + 1120000 + 500000 + 360000 = 6680000
  5. Calculate the sample standard deviation (ss).

    s=∑fi(xi−xˉ)2N−1s = \sqrt{\frac{\sum f_i (x_i - \bar{x})^2}{N-1}} s=6680000100−1s = \sqrt{\frac{6680000}{100-1}} s=668000099s = \sqrt{\frac{6680000}{99}} s=67474.74747...s = \sqrt{67474.74747...} s≈259.75905s \approx 259.75905

    Rounding to two decimal places, the sample standard deviation is 259.76.

    s≈259.76s \approx 259.76
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