Selesaikan. Solve. (i) sqrt(13) x sqrt(13) (ii) 3/(216) + 43. (b) Diberi: Given: Cari nilai a + b. Find the value of a + b. -729 = a x a x a sqrt(49) = b + 2

When a square root is multiplied by itself, the result is the number inside the square root.

$$\sqrt{13} \times \sqrt{13} = \sqrt{13 \times 13} = \sqrt{169}$$

$$\sqrt{169} = 13$$

The solution is $\boxed{13}$.

Find the cube root of the numerator and the denominator separately.

$$\sqrt[3]{27} = 3 \quad (\text{since } 3 \times 3 \times 3 = 27)$$ $$\sqrt[3]{216} = 6 \quad (\text{since } 6 \times 6 \times 6 = 216)$$

So,

$$\sqrt[3]{\frac{27}{216}} = \frac{\sqrt[3]{27}}{\sqrt[3]{216}} = \frac{3}{6}$$

$$\frac{1}{2} + 64 = 64\frac{1}{2} \quad \text{or} \quad 64.5$$

The solution is $\boxed{64\frac{1}{2}}$.

The equation is $-729 = a \times a \times a$, which can be written as $a^3 = -729$.
To find $a$, take the cube root of $-729$.

$$a = \sqrt[3]{-729}$$

Since $9 \times 9 \times 9 = 729$, then $(-9) \times (-9) \times (-9) = -729$.
So, $a = -9$.

The equation is $\sqrt{49} = b + 2$.
First, evaluate $\sqrt{49}$.

$$\sqrt{49} = 7$$

Substitute this value into the equation:

$$7 = b + 2$$

Subtract 2 from both sides to solve for $b$:

$$b = 7 - 2$$ $$b = 5$$

Substitute the values of $a$ and $b$ found in Step 1 and Step 2.

$$a+b = -9 + 5$$ $$a+b = -4$$

The value of $a+b$ is $\boxed{-4}$.