This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Here are the solutions to the problems:
1. Simplify
Step 1: Find a common denominator for 4 and 8, which is 8.
Step 2: Rewrite the first fraction with the common denominator.
Step 3: Add the numerators and combine like terms. The simplified expression is .
2. Simplify
Step 1: Find a common denominator for 6, 3, and 2, which is 6.
Step 2: Rewrite each fraction with the common denominator.
Step 3: Add the numerators and combine like terms.
Step 4: Factor out the common term in the numerator and simplify the fraction. The simplified expression is .
3. Simplify
Step 1: Simplify each fraction individually.
Step 2: Substitute the simplified fractions back into the expression.
Step 3: Subtract the numerators since they have a common denominator.
Step 4: Combine like terms.
Step 5: Simplify the fraction. The simplified expression is .
4. Simplify (Assuming the operation between the two fractions is addition, as it is a common convention when an operator is missing in such problems.)
Step 1: Find a common denominator for 4 and 3, which is 12.
Step 2: Rewrite each fraction with the common denominator.
Step 3: Add the numerators and combine like terms. The simplified expression is .
5. Simplify
Step 1: Calculate the numerators.
Step 2: Substitute the calculated numerators back into the expression.
Step 3: Find a common denominator for 8 and 4, which is 8.
Step 4: Rewrite the second fraction with the common denominator.
Step 5: Subtract the numerators. The simplified expression is .
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1. Simplify (3a+5b)/(4) + (9a+b)/(8) Step 1: Find a common denominator for 4 and 8, which is 8.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.