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Calculate Spearman's rank correlation coefficient for the given ranks.

Mathematics

ScanSolve AI Answer

Answer

0.4\text{0.4}

Step-by-step solution

4 steps

To find Spearman's rank correlation coefficient, we use the formula:

ρ=1−6∑di2n(n2−1)\rho = 1 - \frac{6 \sum d_i^2}{n(n^2 - 1)}

where nn is the number of items and did_i is the difference between the ranks of each item.

  1. List the true ranks (RiR_i) and observed ranks (SiS_i) and calculate the differences (di=Ri−Sid_i = R_i - S_i) and squared differences (di2d_i^2).

    The true order (true ranks) is 1, 2, 3, 4.
    The observed order (observed ranks) is 2, 3, 1, 4.
    The number of items, n=4n = 4.

    ItemTrue Rank (RiR_i)Observed Rank (SiS_i)di=Ri−Sid_i = R_i - S_idi2d_i^2
    1121−2=−11 - 2 = -11
    2232−3=−12 - 3 = -11
    3313−1=23 - 1 = 24
    4444−4=04 - 4 = 00
  2. Calculate the sum of the squared differences, ∑di2\sum d_i^2.

    ∑di2=1+1+4+0=6\sum d_i^2 = 1 + 1 + 4 + 0 = 6
  3. Substitute the values of nn and ∑di2\sum d_i^2 into Spearman's rank correlation coefficient formula.

    ρ=1−6×64(42−1)\rho = 1 - \frac{6 \times 6}{4(4^2 - 1)} ρ=1−364(16−1)\rho = 1 - \frac{36}{4(16 - 1)} ρ=1−364(15)\rho = 1 - \frac{36}{4(15)} ρ=1−3660\rho = 1 - \frac{36}{60}
  4. Simplify the expression to find ρ\rho.

    ρ=1−35\rho = 1 - \frac{3}{5} ρ=1−0.6\rho = 1 - 0.6 ρ=0.4\rho = 0.4

    The value of Spearman's rank correlation coefficient is 0.4\text{0.4}.

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