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Show that expressions A and B are equivalent. Then show that expressions C and D are not.

Mathematics

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Here are the solutions to the questions:

1.1.1 Substitute m=1m=1 in A and B respectively.
For A:

m(2−m)=1(2−1)=1(1)=1m(2-m) = 1(2-1) = 1(1) = 1

For B:

m(−m+2)=1(−1+2)=1(1)=1m(-m+2) = 1(-1+2) = 1(1) = 1

Do you get the same answer? Yes.
Conclusion: The expressions yield the same value when m=1m=1.

1.1.2 Choose another value for mm, and substitute in A and B.
Let m=3m=3.
For A:

m(2−m)=3(2−3)=3(−1)=−3m(2-m) = 3(2-3) = 3(-1) = -3

For B:

m(−m+2)=3(−3+2)=3(−1)=−3m(-m+2) = 3(-3+2) = 3(-1) = -3

Do you get the same answer? Yes.
Conclusion: The expressions yield the same value when m=3m=3.

1.1.3 Multiply out expression A.

A=m(2−m)=2m−m2A = m(2-m) = 2m - m^2

1.1.4 Multiply out expression B.

B=m(−m+2)=−m2+2mB = m(-m+2) = -m^2 + 2m

1.1.5 Are the multiplied-out expressions the same? Explain.
Yes, the multiplied-out expressions are the same.
Explanation: The terms 2m2m and −m2-m^2 are present in both expressions, just in a different order. This demonstrates the commutative property of addition, where a+b=b+aa+b = b+a.

1.2.1 Substitute p=1p=1 in C and D respectively.
For C:

3(p−2)=3(1−2)=3(−1)=−33(p-2) = 3(1-2) = 3(-1) = -3

For D:

3(2−p)=3(2−1)=3(1)=33(2-p) = 3(2-1) = 3(1) = 3

Do you get the same answer? No.
Conclusion: The expressions yield different values when p=1p=1.

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