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What is the area of a triangle where every side is 5 units long correct to the nearest unit?

Mathematics

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Answers

2 parts
7

11 units2\text{11 units}^2

8

1532\frac{15\sqrt{3}}{2}

Step-by-step solution

6 steps

Part 7· 3 steps

What is the area of a triangle where every side is 5 units long correct to the nearest unit?

  1. Identify the type of triangle and its side length.

    Since every side is 5 units long, this is an equilateral triangle with side length s=5s = 5 units.

  2. Apply the formula for the area of an equilateral triangle.

    The area AA of an equilateral triangle is given by the formula:

    A=34s2A = \frac{\sqrt{3}}{4} s^2

    Substitute s=5s = 5:

    A=34(5)2A = \frac{\sqrt{3}}{4} (5)^2 A=34×25A = \frac{\sqrt{3}}{4} \times 25 A=2534A = \frac{25\sqrt{3}}{4}
  3. Calculate the numerical value and round to the nearest unit.

    A≈25×1.732054A \approx \frac{25 \times 1.73205}{4} A≈43.301254A \approx \frac{43.30125}{4} A≈10.8253125A \approx 10.8253125

    Rounding to the nearest unit, we get:

    A≈11 units2A \approx 11 \text{ units}^2

    The area of the triangle is 11 units2\boxed{\text{11 units}^2}.

Part 8

1532\frac{15\sqrt{3}}{2}

Calculate the exact area of △ABC\triangle ABC.

  1. Identify the given sides and included angle.

    From the image, we have side AC=b=5AC = b = 5, side BC=a=6BC = a = 6, and the included angle ∠C=60∘\angle C = 60^\circ.

  2. Apply the formula for the area of a triangle given two sides and the included angle.

    The area AA of a triangle is given by the formula:

    A=12absin⁡(C)A = \frac{1}{2}ab\sin(C)

    Substitute the given values:

    A=12(6)(5)sin⁡(60∘)A = \frac{1}{2} (6)(5)\sin(60^\circ)
  3. Calculate the exact value.

    We know that sin⁡(60∘)=32\sin(60^\circ) = \frac{\sqrt{3}}{2}.

    A=12(30)(32)A = \frac{1}{2} (30) \left(\frac{\sqrt{3}}{2}\right) A=15(32)A = 15 \left(\frac{\sqrt{3}}{2}\right) A=1532A = \frac{15\sqrt{3}}{2}

    The exact area of △ABC\triangle ABC is 1532\boxed{\frac{15\sqrt{3}}{2}}.

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