The general form of the parabola is f(x) = a(x−p)2 + q.

Here's a step-by-step solution to the problem:

The general form of the parabola is $f(x) = a(x-p)^2 + q$.
The axis of symmetry is $x=p$, and the turning point (vertex) is $(p, q)$.
The straight line is $g(x) = -2x - 3$.
Point A(-4; 5) is on the parabola $f(x)$ and on the line $g(x)$.
Let's verify A(-4; 5) is on $g(x)$: $g(-4) = -2(-4) - 3 = 8 - 3 = 5$. So A(-4; 5) is indeed on $g