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The interior angles of a lexagon are 2x°, x°, x+40,110°, 130° and 160°. Find the value of the smallest angle.

Mathematics

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Answer

40∘\text{40}^\circ

Step-by-step solution

5 steps

Huu hapa ni ufumbuzi wa swali la 11:

  1. Tafuta jumla ya pembe za ndani za heksagoni.

    Jumla ya pembe za ndani za poligoni yenye nn pande hutolewa na fomula (n−2)×180∘(n-2) \times 180^\circ. Kwa heksagoni, n=6n=6.

    Jumla ya pembe=(6−2)×180∘=4×180∘=720∘\text{Jumla ya pembe} = (6-2) \times 180^\circ = 4 \times 180^\circ = 720^\circ
  2. Tengeneza mlinganyo kwa kujumlisha pembe zote zilizopewa na kuziweka sawa na jumla ya pembe.

    Pembe zilizopewa ni 2x∘2x^\circ, 12x∘\frac{1}{2}x^\circ, (x+40)∘(x+40)^\circ, 110∘110^\circ, 130∘130^\circ, na 160∘160^\circ.

    2x+12x+(x+40)+110+130+160=7202x + \frac{1}{2}x + (x+40) + 110 + 130 + 160 = 720
  3. Tatua mlinganyo ili kupata thamani ya xx.

    Kwanza, jumlisha vigezo vya xx na namba zisizo na xx:

    (2x+0.5x+x)+(40+110+130+160)=720(2x + 0.5x + x) + (40 + 110 + 130 + 160) = 720 3.5x+440=7203.5x + 440 = 720

    Toa 440 kutoka pande zote mbili:

    3.5x=720−4403.5x = 720 - 440 3.5x=2803.5x = 280

    Gawanya pande zote mbili kwa 3.5:

    x=2803.5x = \frac{280}{3.5} x=80x = 80
  4. Kokotoa kila pembe kwa kutumia thamani ya xx.

    • Pembe ya kwanza: 2x∘=2(80)∘=160∘2x^\circ = 2(80)^\circ = 160^\circ
    • Pembe ya pili: 12x∘=12(80)∘=40∘\frac{1}{2}x^\circ = \frac{1}{2}(80)^\circ = 40^\circ
    • Pembe ya tatu: (x+40)∘=(80+40)∘=120∘(x+40)^\circ = (80+40)^\circ = 120^\circ
    • Pembe ya nne: 110∘110^\circ
    • Pembe ya tano: 130∘130^\circ
    • Pembe ya sita: 160∘160^\circ
  5. Tambua pembe ndogo zaidi.

    Kulinganisha pembe zote: 160∘,40∘,120∘,110∘,130∘,160∘160^\circ, 40^\circ, 120^\circ, 110^\circ, 130^\circ, 160^\circ.
    Pembe ndogo zaidi ni 40∘40^\circ.

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