The problem is to solve 5 - 2x x - 1 and represent the solution on a number line.

Add $2x$ to both sides:

$$5 \le x - 1 + 2x$$ $$5 \le 3x - 1$$

Add 1 to both sides:

$$5 + 1 \le 3x$$ $$6 \le 3x$$

Divide both sides by 3:

$$\frac{6}{3} \le \frac{3x}{3}$$ $$2 \le x$$

This can also be written as $x \ge 2$.

Draw a number line. Place a closed circle at 2 (because $x$ is greater than or equal to 2). Draw an arrow extending to the right from the closed circle, indicating all values greater than 2.

Your solution and number line representation are correct.

Simultaneous Linear Equations:
The system of equations is:

1. $5n + 2m = 10$
2. $3m + 7n = 29$

Your approach to multiply the equations to eliminate a variable is correct, but there was a small arithmetic error in your multiplication of the second equation.

Let's re-solve using the elimination method. We will aim to eliminate $m$.
Rearrange equation (2) to align variables:

1. $5n + 2m = 10$
2. $7n + 3m = 29$

Multiply (1) by 3:

$$3(5n + 2m) = 3(10)$$ $$15n + 6m = 30 \quad \text{(Equation 3)}$$

Multiply (2) by 2:

$$2(7n + 3m) = 2(29)$$ $$14n + 6m = 58 \quad \text{(Equation 4)}$$

(Note: In your work, you had $3 \times 29 = 60$, but $3 \times 29 = 87$. If you were trying to multiply equation (2) by 2, then $2 \times 29 = 58$. Let's proceed with $2 \times 29 = 58$ as per the elimination strategy for $m$.)

$$(15n + 6m) - (14n + 6m) = 30 - 58$$ $$15n - 14n + 6m - 6m = -28$$ $$n = -28$$

Using Equation 1: $5n + 2m = 10$

$$5(-28) + 2m = 10$$ $$-140 + 2m = 10$$

Add 140 to both sides:

$$2m = 10 + 140$$ $$2m = 150$$

Divide by 2:

$$m = \frac{150}{2}$$ $$m = 75$$

The solution is $n = -28$ and $m = 75$.

The final answer is $n = -28, m = 75$.