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What are the solutions for problems 7, 8, and 9? Problem 7 asks to identify a finite set among given options. Problem 8 requires finding f(2) for f(x) = 4x+2. Problem 9 asks for the range and arrow di

Mathematics

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Graph of f(x) = 4x + 2

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Key points of f(x) = 4x + 2
Pointxy
x-intercept−0.50
y-intercept02

Step-by-step solution

10 steps

Here are the solutions to the problems:

7. Which of the following is a finite set?
A. Set of natural numbers
B. Set of all real numbers
C. Set of days in a week
D. Set of all integers

A finite set is a set with a countable number of elements.

  • The set of natural numbers is infinite ({1,2,3,...}\{1, 2, 3, ...\}).
  • The set of all real numbers is infinite.
  • The set of days in a week is finite ({Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}\{\text{Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}\}), containing 7 elements.
  • The set of all integers is infinite ({...,−2,−1,0,1,2,...}\{..., -2, -1, 0, 1, 2, ...\}).

The correct option is C\boxed{\text{C}}.

8. Given the function f(x)=4x+2f(x) = 4x+2, find f(2)f(2).

  1. Substitute x=2x=2 into the function f(x)=4x+2f(x) = 4x+2.

    f(2)=4(2)+2f(2) = 4(2) + 2
  2. Perform the multiplication.

    f(2)=8+2f(2) = 8 + 2
  3. Perform the addition.

    f(2)=10f(2) = 10

    The value of f(2)f(2) is 10\boxed{10}.

    9. Consider the function f(x)=2xf(x) = 2x. If the domain is {0,1,2}\{0, 1, 2\}, find the range values. Hence, draw the arrow diagram.

  4. Calculate the range values by substituting each domain value into the function f(x)=2xf(x) = 2x.

    For x=0x=0:

    f(0)=2(0)=0f(0) = 2(0) = 0

    For x=1x=1:

    f(1)=2(1)=2f(1) = 2(1) = 2

    For x=2x=2:

    f(2)=2(2)=4f(2) = 2(2) = 4

    The range values are {0,2,4}\boxed{\{0, 2, 4\}}.

  5. Draw the arrow diagram.

    Domain: {0,1,2}\{0, 1, 2\}
    Range: {0,2,4}\{0, 2, 4\}
    The arrow diagram shows the mapping from each domain element to its corresponding range element:

    0→00 \to 0 1→21 \to 2 2→42 \to 4

    10. Out of 17 teachers in a school, 10 teach Economics, and 9 teach Maths. The number of teachers who teach both subjects is twice that of those who teach none of the subjects. Use a Venn diagram to find the numbers that teach:

    (a) Both subjects.

    (b) None of the subject.

    (c) Only one subject.

    Let EE be the set of teachers who teach Economics and MM be the set of teachers who teach Maths.
    Total teachers N=17N = 17.
    Number of teachers teaching Economics, ∣E∣=10|E| = 10.
    Number of teachers teaching Maths, ∣M∣=9|M| = 9.

    Let xx be the number of teachers who teach both subjects, i.e., x=∣E∩M∣x = |E \cap M|.
    Let yy be the number of teachers who teach none of the subjects, i.e., y=∣E∪M∣′y = |E \cup M|'.

    From the problem statement, the number of teachers who teach both subjects is twice that of those who teach none:

    x=2yx = 2y

    The number of teachers who teach only Economics is ∣E∣−x=10−x|E| - x = 10 - x.
    The number of teachers who teach only Maths is ∣M∣−x=9−x|M| - x = 9 - x.

    The total number of teachers is the sum of those who teach only Economics, only Maths, both, and none:

    (10−x)+(9−x)+x+y=17(10 - x) + (9 - x) + x + y = 17
  6. Simplify the equation.

    19−x+y=1719 - x + y = 17
  7. Substitute x=2yx = 2y into the simplified equation.

    19−(2y)+y=1719 - (2y) + y = 17 19−y=1719 - y = 17
  8. Solve for yy.

    y=19−17y = 19 - 17 y=2y = 2

    So, the number of teachers who teach none of the subjects is 2.

  9. Solve for xx using x=2yx = 2y.

    x=2(2)x = 2(2) x=4x = 4

    So, the number of teachers who teach both subjects is 4.

  10. Calculate the number of teachers who teach only one subject.

    Number of teachers who teach only Economics =10−x=10−4=6= 10 - x = 10 - 4 = 6.
    Number of teachers who teach only Maths =9−x=9−4=5= 9 - x = 9 - 4 = 5.
    Number of teachers who teach only one subject =6+5=11= 6 + 5 = 11.

    The answers are:

    (a) Both subjects: 4\boxed{4}

    (b) None of the subject: 2\boxed{2}

    (c) Only one subject: 11\boxed{11}

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