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To find the total surface area of the rocket, we need to calculate the area of its exposed surfaces. The rocket is composed of a cylinder and a cone. The exposed surfaces are:

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To find the total surface area of the rocket, we need to calculate the area of its exposed surfaces. The rocket is composed of a cylinder and a cone. The exposed surfaces are:

  1. The circular base of the cylinder.
  2. The lateral surface area of the cylinder.
  3. The lateral surface area of the cone.

The circular face where the cylinder and cone meet is internal and not part of the total external surface area.

From the image, we have the following dimensions:

  • Diameter of the cylinder (and base of the cone) = 4 cm4 \text{ cm}.
  • Radius r=4 cm2=2 cmr = \frac{4 \text{ cm}}{2} = 2 \text{ cm}.
  • Height of the cylinder hcyl=20 cmh_{cyl} = 20 \text{ cm}.
  • Height of the cone hcone=15 cmh_{cone} = 15 \text{ cm}.
  1. Calculate the slant height (ll) of the cone.

    The slant height is found using the Pythagorean theorem:

    l=r2+hcone2l = \sqrt{r^2 + h_{cone}^2} l=(2 cm)2+(15 cm)2l = \sqrt{(2 \text{ cm})^2 + (15 \text{ cm})^2} l=4 cm2+225 cm2l = \sqrt{4 \text{ cm}^2 + 225 \text{ cm}^2} l=229 cml = \sqrt{229} \text{ cm}
  2. Calculate the area of the circular base of the cylinder.

    Abase=πr2A_{base} = \pi r^2 Abase=π(2 cm)2A_{base} = \pi (2 \text{ cm})^2 Abase=4π cm2A_{base} = 4\pi \text{ cm}^2
  3. Calculate the lateral surface area of the cylinder.

    Acyl_lat=2πrhcylA_{cyl\_lat} = 2\pi r h_{cyl} Acyl_lat=2π(2 cm)(20 cm)A_{cyl\_lat} = 2\pi (2 \text{ cm}) (20 \text{ cm}) Acyl_lat=80π cm2A_{cyl\_lat} = 80\pi \text{ cm}^2
  4. Calculate the lateral surface area of the cone.

    Acone_lat=πrlA_{cone\_lat} = \pi r l Acone_lat=π(2 cm)(229 cm)A_{cone\_lat} = \pi (2 \text{ cm}) (\sqrt{229} \text{ cm}) Acone_lat=2π229 cm2A_{cone\_lat} = 2\pi \sqrt{229} \text{ cm}^2
  5. Calculate the total surface area (AtotalA_{total}) by summing the areas of the exposed surfaces.

    Atotal=Abase+Acyl_lat+Acone_latA_{total} = A_{base} + A_{cyl\_lat} + A_{cone\_lat} Atotal=4π cm2+80π cm2+2π229 cm2A_{total} = 4\pi \text{ cm}^2 + 80\pi \text{ cm}^2 + 2\pi \sqrt{229} \text{ cm}^2 Atotal=(84π+2π229) cm2A_{total} = (84\pi + 2\pi \sqrt{229}) \text{ cm}^2

    Factor out 2π2\pi:

    Atotal=2π(42+229) cm2A_{total} = 2\pi (42 + \sqrt{229}) \text{ cm}^2
  6. Calculate the numerical value (using π≈3.14159\pi \approx 3.14159 and 229≈15.1327\sqrt{229} \approx 15.1327).

    Atotal≈2×3.14159×(42+15.1327)A_{total} \approx 2 \times 3.14159 \times (42 + 15.1327) Atotal≈6.28318×57.1327A_{total} \approx 6.28318 \times 57.1327 Atotal≈359.08 cm2A_{total} \approx 359.08 \text{ cm}^2

    The total surface area of the rocket is 2π(42+229) cm2≈359.08 cm2\boxed{2\pi (42 + \sqrt{229}) \text{ cm}^2 \approx 359.08 \text{ cm}^2}.

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