Two circles with centers A and B intersect at points P and Q. Given radius of circle A, AP=AQ=10cm, radius of circle B, BP=BQ=4cm, central angle in circle A, ∠PAQ=52°, and central angle in circle B, ∠

Another one Ronneydomnick — let's solve it. The problem describes two circles with centers A and B, intersecting at points P and Q. Given: Radius of circle A, AP = AQ = 10 cm. Radius of circle B, BP = BQ = 4 cm. Central angle in circle A, PAQ = 52^. Central angle in circle B, PBQ = 97.2^. The line segment AB connects the centers of the circles. The line segment PQ is the common chord. The line AB is the perpendicular bisector of PQ. Let M be the point where AB intersects PQ. Thus, APM and $