Stationing of pvi = 11+700 and the length of the curve is 200m find the stationing of the pvc and pvi

• Stationing of PVI (Point of Vertical Intersection) = $11+700$. This means $11700\, \text{m}$ from the starting reference point.
• Length of the curve ($L$) = $200\, \text{m}$.

For a symmetrical vertical curve, the PVI is located at the midpoint of the curve. Therefore, the distance from PVI to PVC is half the curve length, and the distance from PVI to PVT is also half the curve length.
Distance = $\frac{L}{2} = \frac{200\, \text{m}}{2} = 100\, \text{m}$.

The PVC (Point of Vertical Curvature) is located before the PVI. To find its stationing, subtract the distance calculated in Step 2 from the PVI stationing.
Stationing of PVC = Stationing of PVI - $\frac{L}{2}$
Stationing of PVC = $11700\, \text{m} - 100\, \text{m}$
Stationing of PVC = $11600\, \text{m}$
In stationing notation, this is $11+600$.

The PVT (Point of Vertical Tangency) is located after the PVI. To find its stationing, add the distance calculated in Step 2 to the PVI stationing.
Stationing of PVT = Stationing of PVI + $\frac{L}{2}$
Stationing of PVT = $11700\, \text{m} + 100\, \text{m}$
Stationing of PVT = $11800\, \text{m}$
In stationing notation, this is $11+800$.

The Stationing of PVC is $\boxed{\text{11+600}}$.
The Stationing of PVT is $\boxed{\text{11+800}}$.