Step 1: Understand the given function.
We are given the function h(x)=x2+2x−4.
Step 2: Solve part a).
a) Find h(b+a).
Substitute x=(b+a) into the function:
h(b+a)=(b+a)2+2(b+a)−4
Expand the terms:
h(b+a)=(b2+2ab+a2)+(2b+2a)−4
h(b+a)=a2+b2+2ab+2a+2b−4
The simplified expression is a2+b2+2ab+2a+2b−4.
Step 3: Solve part b).
b) Find h(a−b).
Substitute x=(a−b) into the function:
h(a−b)=(a−b)2+2(a−b)−4
Expand the terms:
h(a−b)=(a2−2ab+b2)+(2a−2b)−4
h(a−b)=a2+b2−2ab+2a−2b−4
The simplified expression is a2+b2−2ab+2a−2b−4.
Step 4: Solve part c).
c) Find bh(1+b)−h(1).
First, find h(1+b):
h(1+b)=(1+b)2+2(1+b)−4
h(1+b)=(1+2b+b2)+(2+2b)−4
h(1+b)=b2+4b+3−4
h(1+b)=b2+4b−1
Next, find h(1):
h(1)=(1)2+2(1)−4
h(1)=1+2−4
h(1)=−1
Now, substitute these into the expression:
bh(1+b)−h(1)=b(b2+4b−1)−(−1)
bh(1+b)−h(1)=bb2+4b−1+1
bh(1+b)−h(1)=bb2+4b
Factor out b from the numerator:
bh(1+b)−h(1)=bb(b+4)
Cancel b (assuming b=0):
bh(1+b)−h(1)=b+4
The simplified expression is b+4.
Step 5: Solve part d).
d) Find bh(a+b)−h(a).
First, find h(a+b):
h(a+b)=(a+b)2+2(a+b)−4
h(a+b)=a2+2ab+b2+2a+2b−4
Next, find h(a):
h(a)=a2+2a−4
Now, substitute these into the expression:
bh(a+b)−h(a)=b(a2+2ab+b2+2a+2b−4)−(a2+2a−4)
Distribute the negative sign in the numerator:
bh(a+b)−h(a)=ba2+2ab+b2+2a+2b−4−a2−2a+4
Combine like terms in the numerator:
bh(a+b)−h(a)=b(a2−a2)+(2a−2a)+(−4+4)+2ab+b2+2b
bh(a+b)−h(a)=b2ab+b2+2b
Factor out b from the numerator:
bh(a+b)−h(a)=bb(2a+b+2)
Cancel b (assuming b=0):
bh(a+b)−h(a)=2a+b+2
The simplified expression is 2a+b+2.