UNIVERSITY OF PORT HARCOURT MANAGEMENT DEPARTMENT, 2025/2026 SESSION SECOND TERM CCE EXAM COURSE CODE: AMS 102.2: BUSINESS MATHEMATICS TIME: 2 HOURS INSTRUCTIONS: Answer Question One (1) and Any Other Three (3) Questions.

Here's the solution for question 1a) (i): Step 1: Simplify the expression for P₁. P₁ = 3x − 2x + 4; P₁ = (3−2)x + 4; P₁ = x + 4 Step 2: Add P₁ and P₂. P₁ + P₂ = (x + 4) + (x² + 2); P₁ + P₂ = x² + x + 4 + 2; P₁ + P₂ = x² + x + 6 The sum of P₁ and P₂ is: x² + x + 6

UNIVERSITY OF PORT HARCOURT MANAGEMENT DEPARTMENT, 2025/2026 SESSION SECOND TERM CCE EXAM COURSE CODE: AMS 102.2: BUSINESS MATHEMATICS TIME: 2 HOURS INSTRUCTIONS: Answer Question One (1) and Any Other Three (3) Questions.

Here's the solution for question 1a) (i): Step 1: Simplify the expression for P₁. P₁ = 3x − 2x + 4; P₁ = (3−2)x + 4; P₁ = x + 4 Step 2: Add P₁ and P₂. P₁ + P₂ = (x + 4) + (x² + 2); P₁ + P₂ = x² + x + 4 + 2; P₁ + P₂ = x² + x + 6 The sum of P₁ and P₂ is: x² + x + 6

Solved: UNIVERSITY OF PORT HARCOURT MANAGEMENT DEPARTMENT…

Here's the solution for question 1a) (i):

Simplify the expression for $P_1$ .
$P_1 = 3x - 2x + 4$ $P_1 = (3-2)x + 4$ $P_1 = x + 4$
Add $P_1$ and $P_2$ .
$P_1 + P_2 = (x + 4) + (x^2 + 2)$ $P_1 + P_2 = x^2 + x + 4 + 2$ $P_1 + P_2 = x^2 + x + 6$
The sum of $P_1$ and $P_2$ is:
$\boxed{x^2 + x + 6}$

UNIVERSITY OF PORT HARCOURT MANAGEMENT DEPARTMENT, 2025/2026 SESSION SECOND TERM CCE EXAM COURSE CODE: AMS 102.2: BUSINESS MATHEMATICS TIME: 2 HOURS INSTRUCTIONS: Answer Question One (1) and Any Other Three (3) Questions.

Step-by-step solution

Simplify the expression for $P_1$ .

Add $P_1$ and $P_2$ .

Still stuck on this one?

More Mathematics Questions

UNIVERSITY OF PORT HARCOURT MANAGEMENT DEPARTMENT, 2025/2026 SESSION SECOND TERM CCE EXAM COURSE CODE: AMS 102.2: BUSINESS MATHEMATICS TIME: 2 HOURS INSTRUCTIONS: Answer Question One (1) and Any Other Three (3) Questions.

Step-by-step solution

Simplify the expression for P1P_1P1​.

Add P1P_1P1​ and P2P_2P2​.

Still stuck on this one?

More Mathematics Questions

Simplify the expression for $P_1$ .

Add $P_1$ and $P_2$ .