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Water is dispensed at a rate of 0.25 litres per second at a station. How long (in minutes) will it take to dispense 50 litres of water?

Mathematics

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Answer

600 bottles\text{600 bottles}

5 minutes and 0 seconds\text{5 minutes and 0 seconds}

3.33 minutes\text{3.33 minutes}

Step-by-step solution

4 steps

  1. Calculate the number of bottles needed for 1.1.5.

    The total water required is 300 L (from the previous calculation for 1.1.1). Each bottle holds 500 ml.
    First, convert the total water required from litres to millilitres.

    300 L×1000 ml/L=300,000 ml300 \text{ L} \times 1000 \text{ ml/L} = 300,000 \text{ ml}

    Next, divide the total millilitres by the volume per bottle to find the number of bottles.

    Number of bottles=300,000 ml500 ml/bottle=600 bottles\text{Number of bottles} = \frac{300,000 \text{ ml}}{500 \text{ ml/bottle}} = 600 \text{ bottles} 600 bottles\boxed{\text{600 bottles}}

  2. Address question 1.1.6.

    The total duration of the event is not provided in the given information. Therefore, this question cannot be answered.

  3. Calculate the time to complete the race for 1.1.7.

    The distance of the race is 1500 m, and the average speed is 5 m/s.
    Use the formula: Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}}.

    Time in seconds=1500 m5 m/s=300 s\text{Time in seconds} = \frac{1500 \text{ m}}{5 \text{ m/s}} = 300 \text{ s}

    Now, convert the total seconds into minutes and seconds. There are 60 seconds in 1 minute.

    Minutes=300 s60 s/min=5 min\text{Minutes} = \frac{300 \text{ s}}{60 \text{ s/min}} = 5 \text{ min} Remaining seconds=300 s−(5 min×60 s/min)=300 s−300 s=0 s\text{Remaining seconds} = 300 \text{ s} - (5 \text{ min} \times 60 \text{ s/min}) = 300 \text{ s} - 300 \text{ s} = 0 \text{ s}

    So, the time taken is 5 minutes and 0 seconds.

    5 minutes and 0 seconds\boxed{\text{5 minutes and 0 seconds}}

  4. Calculate the time to dispense water for 1.1.8.

    Water is dispensed at a rate of 0.25 litres per second, and 50 litres of water need to be dispensed.
    Use the formula: Time=Total VolumeRate\text{Time} = \frac{\text{Total Volume}}{\text{Rate}}.

    Time in seconds=50 L0.25 L/s=200 s\text{Time in seconds} = \frac{50 \text{ L}}{0.25 \text{ L/s}} = 200 \text{ s}

    Now, convert the total seconds into minutes.

    Time in minutes=200 s60 s/min=3.333... min\text{Time in minutes} = \frac{200 \text{ s}}{60 \text{ s/min}} = 3.333... \text{ min}

    To express this more precisely, it's 3 minutes and 20 seconds (0.333...×60=200.333... \times 60 = 20). However, the question asks for the time in minutes.

    Time in minutes=20060=103 min≈3.33 min\text{Time in minutes} = \frac{200}{60} = \frac{10}{3} \text{ min} \approx 3.33 \text{ min} 3.33 minutes\boxed{\text{3.33 minutes}}
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