Water is dispensed at a rate of 0.25 litres per second at a station. How long (in minutes) will it take to dispense 50 litres of water?

Step 1: Calculate the number of bottles needed for 1.1.5. The total water required is 300 L (from the previous calculation for 1.1.1). Each bottle holds 500 ml. First, convert the total water required from litres to millilitres. $300 L \times 1000 ml/L = 300,000 ml$ Next, divide the total millilitres by the volume per bottle to find the number of bottles. $Number of bottles = \frac{300,000 ml}{500 ml/bottle} = 600 bottles$ $\text{600 bottles}$

Step 2: Address question 1.1.6. The total duration of the event is not provided in the given information. Therefore, this question cannot be answered.

Step 3: Calculate the time to complete the race for 1.1.7. The distance of the race is 1500 m, and the average speed is 5 m/s. Use the formula: $\text{Time} = \frac{Distance}{Speed}$. $Time in seconds = \frac{1500 m}{5 m/s} = 300 s$ Now, convert the total seconds into minutes and seconds. There are 60 seconds in 1 minute. $Minutes = \frac{300 s}{60 s/min} = 5 min$ $Remaining seconds = 300 s - (5 min \times 60 s/min) = 300 s - 300 s = 0 s$ So, the time taken is 5 minutes and 0 seconds. $\text{5 minutes and 0 seconds}$

Step 4: Calculate the time to dispense water for 1.1.8. Water is dispensed at a rate of 0.25 litres per second, and 50 litres of water need to be dispensed. Use the formula: $\text{Time} = \frac{Total Volume}{Rate}$. $Time in seconds = \frac{50 L}{0.25 L/s} = 200 s$ Now, convert the total seconds into minutes. $Time in minutes = \frac{200 s}{60 s/min} = 3.333... min$ To express this more precisely, it's 3 minutes and 20 seconds ($0.333... \times 60 = 20$). However, the question asks for the time in minutes. $Time in minutes = \frac{200}{60} = \frac{10}{3} min \approx 3.33 min$ $\text{3.33 minutes}$ That's 2 down. 3 left today — send the next one.