A 40 kg box is pulled up an incline of 15 degrees by a horizontal force of 200 N. If the box moves 20 m at constant velocity, what is the work done against friction?

To solve this problem, we need to calculate the work done by the man and the work done against friction. We are given that the box moves at a constant velocity, which implies that the net force on the box along the incline is zero.

Given values:

• Mass of the box, $m = 40 \, \text{kg}$
• Angle of incline, $\theta = 15^\circ$
• Horizontal force applied by the man, $F_H = 200 \, \text{N}$
• Distance moved up the plane, $d = 20 \, \text{m}$
• Coefficient of kinetic friction, $\mu_k = 0.10$
• Acceleration due to gravity