This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Welcome back — been a while! Let's pick up where you left off. Here are the calculations for the floating block: Given: Cross-sectional area of the block, A = 6.0 cm^2 = 6.0 × 10^-4 m^2 Density of liquid A, _A = 800 kg/m^3 Density of liquid B, _B = 1000 kg/m^3 Height of block submerged in liquid A, h_A = 2 cm = 0.02 m Height of block submerged in liquid B, h_B = 2 cm = 0.02 m Total height of the block, H_total = 2 cm + 2 cm + 2 cm = 6 cm = 0.06 m Acceleration due to gravity, g = 9.8 m/s^2 i) Weight of liquid A displaced Step 1: Calculate the volume of liquid A displaced. V_A = A × h_A V_A = (6.0 × 10^-4 m^2) × (0.02 m) V_A = 1.2 × 10^-5 m^3 Step 2: Calculate the weight of liquid A displaced. W_A = _A V_A g W_A = (800 kg/m^3) × (1.2 × 10^-5 m^3) × (9.8 m/s^2) W_A = 0.09408 N The weight of liquid A displaced is 0.09408 N. ii) Weight of liquid B displaced Step 1: Calculate the volume of liquid B displaced. V_B = A × h_B V_B = (6.0 × 10^-4 m^2) × (0.02 m) V_B = 1.2 × 10^-5 m^3 Step 2: Calculate the weight of liquid B displaced. W_B =