This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Identify the given values. The capacitance of the capacitor is C = 5 mF. The potential difference across the capacitor is V = 10,000 V. Step 2: Convert the capacitance to Farads. C = 5 mF = 5 × 10^-3 F Step 3: Use the formula for the energy stored in a capacitor. The energy E stored in a capacitor is given by the formula: E = (1)/(2) C V^2 Step 4: Substitute the values and calculate the energy. E = (1)/(2) (5 × 10^-3 F) (10,000 V)^2 E = (1)/(2) (5 × 10^-3) (10^4)^2 E = (1)/(2) (5 × 10^-3) (10^8) E = (1)/(2) (5 × 10^8-3) E = (1)/(2) (5 × 10^5) E = 2.5 × 10^5 J E = 250,000 J This can also be expressed as 250 kJ. The energy stored in the capacitor is 250,000 J. Send me the next one 📸