This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Identify the given values. The energy stored in the capacitor (E) is 20.0 J. The voltage across the capacitor (V) is 60.0 V. Step 2: Recall the formula for the energy stored in a capacitor. The energy stored in a capacitor is given by the formula: E = (1)/(2) C V^2 where C is the capacitance and V is the voltage. Step 3: Rearrange the formula to solve for capacitance (C). To find C, we can rearrange the formula: 2E = C V^2 C = (2E)/(V^2) Step 4: Substitute the given values and calculate the capacitance. C = 2 × 20.0 J(60.0 V)^2 C = 40.0 J3600 V^2 C = (1)/(90) F C ≈ 0.0111 F The capacitance of the capacitor is approximately 0.0111 F. 0.0111 F Drop the next question 📸