This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Identify the given values from the diagram. The capacitance of the capacitor is C = 8 F. The voltage across the capacitor is V = 10 V. Step 2: Convert the capacitance to Farads. C = 8 F = 8 × 10^-6 F Step 3: Use the formula for the energy stored in a capacitor. The energy E stored in a capacitor is given by the formula: E = (1)/(2)CV^2 Step 4: Substitute the values into the formula and calculate the energy. E = (1)/(2) (8 × 10^-6 F) (10 V)^2 E = (1)/(2) (8 × 10^-6 F) (100 V^2) E = (4 × 10^-6) × 100 J E = 400 × 10^-6 J E = 4 × 10^-4 J The energy stored in the capacitor is 4 × 10^-4 J.