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A child slides up a playground ramp with a speed of 4 m/s. How high up the ramp will the child go? (Assume no friction.)

Physics

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Question 3:

a) A child slides up a playground ramp with a speed of 4 m/s4 \text{ m/s}. How high up the ramp will the child go?

  1. Identify the given values and the physical principle.

    The initial speed (velocity) of the child is v=4 m/sv = 4 \text{ m/s}.
    We need to find the maximum height hh.
    The acceleration due to gravity is g=9.8 m/s2g = 9.8 \text{ m/s}^2.
    When the child slides up the ramp, their initial kinetic energy is converted into gravitational potential energy at the maximum height. We use the principle of conservation of mechanical energy:

    12mv2=mgh\frac{1}{2}mv^2 = mgh

    The mass mm of the child cancels out from both sides.

  2. Rearrange the formula to solve for the height hh.

    12v2=gh\frac{1}{2}v^2 = gh h=v22gh = \frac{v^2}{2g}
  3. Substitute the given values into the formula and calculate the height.

    h=(4 m/s)22×9.8 m/s2h = \frac{(4 \text{ m/s})^2}{2 \times 9.8 \text{ m/s}^2} h=16 m2/s219.6 m/s2h = \frac{16 \text{ m}^2/\text{s}^2}{19.6 \text{ m/s}^2} h≈0.82 mh \approx 0.82 \text{ m}

    The child will go 0.82 m\boxed{\text{0.82 m}} high up the ramp.

    Question 8:

    a) A truck of mass 2000 kg2000 \text{ kg} moves up a hill at 20 m/s20 \text{ m/s}. Find the maximum height reached. Then state whether mass affects the height.

  4. Identify the given values and the physical principle.

    The mass of the truck is m=2000 kgm = 2000 \text{ kg}.
    The initial speed (velocity) of the truck is v=20 m/sv = 20 \text{ m/s}.
    We need to find the maximum height hh.
    The acceleration due to gravity is g=9.8 m/s2g = 9.8 \text{ m/s}^2.
    Using the principle of conservation of mechanical energy:

    12mv2=mgh\frac{1}{2}mv^2 = mgh

    Again, the mass mm cancels out from both sides.

  5. Rearrange the formula to solve for the height hh.

    12v2=gh\frac{1}{2}v^2 = gh h=v22gh = \frac{v^2}{2g}
  6. Substitute the given values into the formula and calculate the height.

    h=(20 m/s)22×9.8 m/s2h = \frac{(20 \text{ m/s})^2}{2 \times 9.8 \text{ m/s}^2} h=400 m2/s219.6 m/s2h = \frac{400 \text{ m}^2/\text{s}^2}{19.6 \text{ m/s}^2} h≈20.41 mh \approx 20.41 \text{ m}

    The maximum height reached by the truck is 20.41 m\boxed{\text{20.41 m}}.

  7. State whether mass affects the height.

    As seen in the formula h=v22gh = \frac{v^2}{2g}, the mass mm is not present. This means that for a given initial velocity, the maximum height reached is independent of the mass of the object.
    No, the mass does not affect the height reached.

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