We read your photo as:

A container has 0.05 m3 of gas at 1.99 x 105 Pa and 27C. The gas is compressed to 0.02 m3 at 127C. What is the final gauge pressure?

Physics

ScanSolve AI Answer

Question 2:

Step 1: Identify the given values and convert temperatures to Kelvin.
Initial gauge pressure Pgauge,1=1.99×105 PaP_{gauge,1} = 1.99 \times 10^5 \text{ Pa}.
Initial volume V1=0.05 m3V_1 = 0.05 \text{ m}^3.
Initial temperature T1=27∘C=27+273=300 KT_1 = 27^\circ \text{C} = 27 + 273 = 300 \text{ K}.
Final volume V2=0.02 m3V_2 = 0.02 \text{ m}^3.
Final temperature $T_2 = 127^\circ C = 127 + 2

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp