a) Element P forms an ion P²⁻ with electron arrangement 2.8.8.

a) Element P forms an ion P²⁻ with electron arrangement 2.8.8. This means the neutral atom P has 18 − 2 = 16 electrons. The electron arrangement of neutral P is 2.8.6. Step 1: Determine the period. The number of electron shells is 3. Period: 3 Step 2: Determine the group. The number of valence electrons is 6. Group: 16 (or VI) b) Element N has an ion N' with electron arrangement 2.8. This implies N' is N³⁻, so neutral N has 7 electrons with electron arrangement 2.5 (5 valence electrons). Element O has an ion

a) Element P forms an ion P²⁻ with electron arrangement 2.8.8.

a) Element P forms an ion P²⁻ with electron arrangement 2.8.8. This means the neutral atom P has 18 − 2 = 16 electrons. The electron arrangement of neutral P is 2.8.6. Step 1: Determine the period. The number of electron shells is 3. Period: 3 Step 2: Determine the group. The number of valence electrons is 6. Group: 16 (or VI) b) Element N has an ion N' with electron arrangement 2.8. This implies N' is N³⁻, so neutral N has 7 electrons with electron arrangement 2.5 (5 valence electrons). Element O has an ion

Solved: A) Element P forms an ion P²⁻ with electron…

This means the neutral atom P has 18 - 2 = 16 electrons.
The electron arrangement of neutral P is 2.8.6.

A) Element P forms an ion P²⁻ with electron arrangement 2.8.8.

Step-by-step solution

Part a· 2 steps

Determine the period.

Determine the group.

Part b

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