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A large pulley with a diameter of 1300 mm rotates at 230 r/min. determine the belt velocity if the belt is 10 mm thick.

Physics

ScanSolve AI Answer

Answer

15.79 m/s\text{15.79 m/s}

Step-by-step solution

3 steps
  1. Identify the given values and convert them to standard units.

    Pulley diameter, Dp=1300 mm=1.3 mD_p = 1300 \text{ mm} = 1.3 \text{ m}.
    Rotational speed, N=230 r/minN = 230 \text{ r/min}.
    Belt thickness, t=10 mm=0.01 mt = 10 \text{ mm} = 0.01 \text{ m}.

  2. Calculate the effective diameter (DeffD_{eff}) for the belt's center line.

    The belt velocity is measured at the center of the belt's thickness.

    Deff=Dp+tD_{eff} = D_p + t Deff=1.3 m+0.01 mD_{eff} = 1.3 \text{ m} + 0.01 \text{ m} Deff=1.31 mD_{eff} = 1.31 \text{ m}
  3. Calculate the belt velocity (vv).

    The formula for belt velocity is:

    v=πDeffN60v = \frac{\pi D_{eff} N}{60} v=π×1.31 m×230 r/min60 s/minv = \frac{\pi \times 1.31 \text{ m} \times 230 \text{ r/min}}{60 \text{ s/min}} v=π×1.31×23060 m/sv = \frac{\pi \times 1.31 \times 230}{60} \text{ m/s} v≈15.79 m/sv \approx 15.79 \text{ m/s}

    The belt velocity is approximately 15.79 m/s\text{15.79 m/s}.

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